Lemma 90.12.2. Let \mathcal{F} be a predeformation category such that \overline{\mathcal{F}} satisfies (S2)1. Then T \mathcal{F} has a natural k-vector space structure. For any finite dimensional vector space V we have \overline{\mathcal{F}}(k[V]) = T\mathcal{F} \otimes _ k V functorially in V.
Proof. Let us write F = \overline{\mathcal{F}} : \mathcal{C}_\Lambda \to \textit{Sets}. This is a predeformation functor and F satisfies (S2). By Lemma 90.10.4 (and the translation of Remark 90.10.3) we see that
F(A \times _ k k[V]) \longrightarrow F(A) \times F(k[V])
is a bijection for every finite dimensional vector space V and every A \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{C}_\Lambda ). In particular, if A = k[W] then we see that F(k[W] \times _ k k[V]) = F(k[W]) \times F(k[V]). In other words, the hypotheses of Lemma 90.11.8 hold and we see that TF = T \mathcal{F} has a natural k-vector space structure. The final assertion follows from Lemma 90.11.15. \square
Comments (0)
There are also: