Lemma 78.27.1. Notation and assumption as in Lemma 78.21.1. The morphism of quotient stacks
[f] : [U/R] \longrightarrow [U'/R']
turns [U/R] into a gerbe over [U'/R'] if f : U \to U' and R \to R'|_ U are surjective maps of fppf sheaves. Here R'|_ U is the restriction of R' to U via f : U \to U'.
Proof.
We will verify that Stacks, Lemma 8.11.3 properties (2) (a) and (2) (b) hold. Property (2)(a) holds because U \to U' is a surjective map of sheaves (use Lemma 78.24.1 to see that objects in [U'/R'] locally come from U'). To prove (2)(b) let x, y be objects of [U/R] over a scheme T/S. Let x', y' be the images of x, y in the category [U'/'R]_ T. Condition (2)(b) requires us to check the map of sheaves
\mathit{Isom}(x, y) \longrightarrow \mathit{Isom}(x', y')
on (\mathit{Sch}/T)_{fppf} is surjective. To see this we may work fppf locally on T and assume that come from a, b \in U(T). In that case we see that x', y' correspond to f \circ a, f \circ b. By Lemma 78.22.1 the displayed map of sheaves in this case becomes
T \times _{(a, b), U \times _ B U} R \longrightarrow T \times _{f \circ a, f \circ b, U' \times _ B U'} R' = T \times _{(a, b), U \times _ B U} R'|_ U.
Hence the assumption that R \to R'|_ U is a surjective map of fppf sheaves on (\mathit{Sch}/S)_{fppf} implies the desired surjectivity.
\square
Comments (0)
There are also: