The Stacks project

Lemma 30.4.4. Let $X$ be a quasi-compact quasi-separated scheme. Let $X = U_1 \cup \ldots \cup U_ t$ be an affine open covering. Set

\[ d = \max \nolimits _{I \subset \{ 1, \ldots , t\} } \left(|I| + t(\bigcap \nolimits _{i \in I} U_ i)\right) \]

where $t(U)$ is the minimal number of affines needed to cover the scheme $U$. Then $H^ n(X, \mathcal{F}) = 0$ for all $n \geq d$ and all quasi-coherent sheaves $\mathcal{F}$.

Proof. Note that since $X$ is quasi-separated the numbers $t(\bigcap _{i \in I} U_ i)$ are finite. Let $\mathcal{U} : X = \bigcup _{i = 1}^ t U_ i$. By Cohomology, Lemma 20.11.5 there is a spectral sequence

\[ E_2^{p, q} = \check{H}^ p(\mathcal{U}, \underline{H}^ q(\mathcal{F})) \]

converging to $H^{p + q}(U, \mathcal{F})$. By Cohomology, Lemma 20.23.6 we have

\[ E_2^{p, q} = H^ p(\check{\mathcal{C}}_{alt}^\bullet ( \mathcal{U}, \underline{H}^ q(\mathcal{F})) \]

The alternating Čech complex with values in the presheaf $\underline{H}^ q(\mathcal{F})$ vanishes in high degrees by Lemma 30.4.2, more precisely $E_2^{p, q} = 0$ for $p + q \geq d$. Hence the result follows. $\square$

Comments (2)

Comment #7726 by Ryo Suzuki on

This lemma can be proved in the same fashion with first proof of lemma 30.4.2. Moreover, it can be slightly strengthened the statement.

First, reformulate the statement as follows: Let X be a quasi-compact quasi-separated scheme. Let be an open covering where is quasi-compact separated. Set . Then for and all quasi-coherent sheaf .

I will prove it by induction on . If , the result follows from 30.4.2. If , write with quasi-compact separated and . Notice that can be written as , where is quasi-compact separated.

Let , , , . So, By induction we have for , for , and for . By Mayer-Vietoris sequence, for .

There are also:

  • 5 comment(s) on Section 30.4: Quasi-coherence of higher direct images

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.

In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 071L. Beware of the difference between the letter 'O' and the digit '0'.