Lemma 29.25.16. Let f : X \to Y be a flat morphism of schemes. Let g : V \to Y be a quasi-compact morphism of schemes. Let Z \subset Y be the scheme theoretic image of g and let Z' \subset X be the scheme theoretic image of the base change V \times _ Y X \to X. Then Z' = f^{-1}Z.
Taking scheme theoretic images commutes with flat base change in the quasi-compact case
Proof. Recall that Z is cut out by \mathcal{I} = \mathop{\mathrm{Ker}}(\mathcal{O}_ Y \to g_*\mathcal{O}_ V) and Z' is cut out by \mathcal{I}' = \mathop{\mathrm{Ker}}(\mathcal{O}_ X \to (V \times _ Y X \to X)_*\mathcal{O}_{V \times _ Y X}), see Lemma 29.6.3. Hence the question is local on X and Y and we may assume X and Y affine. Note that we may replace V by \coprod V_ i where V = V_1 \cup \ldots \cup V_ n is a finite affine open covering. Hence we may assume g is affine. In this case (V \times _ Y X \to X)_*\mathcal{O}_{V \times _ Y X} is the pullback of g_*\mathcal{O}_ V by f. Since f is flat we conclude that f^*\mathcal{I} = \mathcal{I}' and the lemma holds. \square
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