The Stacks project

Lemma 36.9.3. In Situation 36.9.1. Let $M^\bullet $ be a complex of $A$-modules and denote $\mathcal{F}^\bullet $ the associated complex of $\mathcal{O}_ X$-modules. Then there is a canonical isomorphism of complexes

\[ \mathop{\mathrm{colim}}\nolimits _ e \mathop{\mathrm{Hom}}\nolimits ^\bullet (I^\bullet (f_1^ e, \ldots , f_ r^ e), M^\bullet ) \longrightarrow \text{Tot}(\check{\mathcal{C}}_{alt}^\bullet (\mathcal{U}, \mathcal{F}^\bullet )) \]

functorial in $M^\bullet $.

Proof. Consider the double complex $F^{\bullet , \bullet }$ with terms $F^{p, q} = \mathcal{C}_{alt}^ p(\mathcal{U}, \mathcal{F}^ q)$ discussed in Cohomology, Section 20.25. Consider the double complex $G^{\bullet , \bullet }$ with terms $G^{p, q} = \mathop{\mathrm{colim}}\nolimits _ e \mathop{\mathrm{Hom}}\nolimits _ A(I^{-p}(f_1^ e, \ldots , f_ r^ e), M^ q)$ and differentials given by functoriality (without the intervention of signs). The maps $\psi ^{p, q} : G^{p, q} \to F^{p, q}$ constructed in the proof of Lemma 36.9.2 are isomorphisms and compatible with the differentials $d_1$ (by the lemma) and $d_2$ (this is clear). However, the differentials $d$ on the complexes on the left and right hand side of the arrow in the lemma have different signs. Namely, for $g \in G^{p, q}$ is given by

\[ d(g) = d_2(g) - (-1)^{p + q} d_1(g) \]

(see More on Algebra, Section 15.71) and the differential for $f \in F^{p, q}$ is given by

\[ d(f) = d_1(f) + (-1)^ p d_2(f) \]

Thus we can fix the signs by multiplying $\psi ^{p, q}$ by $(-1)^{pq + p(p - 1)/2}$. $\square$


Comments (0)

There are also:

  • 3 comment(s) on Section 36.9: Koszul complexes

Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 08D1. Beware of the difference between the letter 'O' and the digit '0'.