Lemma 36.22.1. Let f : X \to Y be a quasi-compact and quasi-separated morphism of schemes. For E in D_\mathit{QCoh}(\mathcal{O}_ X) and K in D_\mathit{QCoh}(\mathcal{O}_ Y) the map
defined in Cohomology, Equation (20.54.2.1) is an isomorphism.
Lemma 36.22.1. Let f : X \to Y be a quasi-compact and quasi-separated morphism of schemes. For E in D_\mathit{QCoh}(\mathcal{O}_ X) and K in D_\mathit{QCoh}(\mathcal{O}_ Y) the map
defined in Cohomology, Equation (20.54.2.1) is an isomorphism.
Proof. To check the map is an isomorphism we may work locally on Y. Hence we reduce to the case that Y is affine.
Suppose that K = \bigoplus K_ i is a direct sum of some complexes K_ i \in D_\mathit{QCoh}(\mathcal{O}_ Y). If the statement holds for each K_ i, then it holds for K. Namely, the functors Lf^* and \otimes ^\mathbf {L} preserve direct sums by construction and Rf_* commutes with direct sums (for complexes with quasi-coherent cohomology sheaves) by Lemma 36.4.5. Moreover, suppose that K \to L \to M \to K[1] is a distinguished triangle in D_\mathit{QCoh}(Y). Then if the statement of the lemma holds for two of K, L, M, then it holds for the third (as the functors involved are exact functors of triangulated categories).
Assume Y affine, say Y = \mathop{\mathrm{Spec}}(A). The functor \widetilde{\ } : D(A) \to D_\mathit{QCoh}(\mathcal{O}_ Y) is an equivalence (Lemma 36.3.5). Let T be the property for K \in D(A) that the statement of the lemma holds for \widetilde{K}. The discussion above and More on Algebra, Remark 15.59.11 shows that it suffices to prove T holds for A[k]. This finishes the proof, as the statement of the lemma is clear for shifts of the structure sheaf. \square
Comments (1)
Comment #9718 by Shubhankar on