Processing math: 100%

The Stacks project

36.18 Derived categories as module categories

In this section we draw some conclusions of what has gone before. Before we do so we need a couple more lemmas.

Lemma 36.18.1. Let X be a scheme. Let K^\bullet be a complex of \mathcal{O}_ X-modules whose cohomology sheaves are quasi-coherent. Let (E, d) = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(K^\bullet , K^\bullet ) be the endomorphism differential graded algebra. Then the functor

- \otimes _ E^\mathbf {L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O}_ X)

of Differential Graded Algebra, Lemma 22.35.3 has image contained in D_\mathit{QCoh}(\mathcal{O}_ X).

Proof. Let P be a differential graded E-module with property (P) and let F_\bullet be a filtration on P as in Differential Graded Algebra, Section 22.20. Then we have

P \otimes _ E K^\bullet = \text{hocolim}\ F_ iP \otimes _ E K^\bullet

Each of the F_ iP has a finite filtration whose graded pieces are direct sums of E[k]. The result follows easily. \square

The following result is taken from [BvdB].

Theorem 36.18.2. Let X be a quasi-compact and quasi-separated scheme. Then there exist a differential graded algebra (E, \text{d}) with only a finite number of nonzero cohomology groups H^ i(E) such that D_\mathit{QCoh}(\mathcal{O}_ X) is equivalent to D(E, \text{d}).

Proof. Let K^\bullet be a K-injective complex of \mathcal{O}-modules which is perfect and generates D_\mathit{QCoh}(\mathcal{O}_ X). Such a thing exists by Theorem 36.15.3 and the existence of K-injective resolutions. We will show the theorem holds with

(E, \text{d}) = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(K^\bullet , K^\bullet )

where \text{Comp}^{dg}(\mathcal{O}_ X) is the differential graded category of complexes of \mathcal{O}-modules. Please see Differential Graded Algebra, Section 22.35. Since K^\bullet is K-injective we have

36.18.2.1
\begin{equation} \label{perfect-equation-E-is-OK} H^ n(E) = \mathop{\mathrm{Ext}}\nolimits ^ n_{D(\mathcal{O}_ X)}(K^\bullet , K^\bullet ) \end{equation}

for all n \in \mathbf{Z}. Only a finite number of these Exts are nonzero by Lemma 36.13.5. Consider the functor

- \otimes _ E^\mathbf {L} K^\bullet : D(E, \text{d}) \longrightarrow D(\mathcal{O}_ X)

of Differential Graded Algebra, Lemma 22.35.3. Since K^\bullet is perfect, it defines a compact object of D(\mathcal{O}_ X), see Proposition 36.17.1. Combined with (36.18.2.1) the functor above is fully faithful as follows from Differential Graded Algebra, Lemmas 22.35.6. It has a right adjoint

R\mathop{\mathrm{Hom}}\nolimits (K^\bullet , - ) : D(\mathcal{O}_ X) \longrightarrow D(E, \text{d})

by Differential Graded Algebra, Lemmas 22.35.5 which is a left quasi-inverse functor by generalities on adjoint functors. On the other hand, it follows from Lemma 36.18.1 that we obtain

- \otimes _ E^\mathbf {L} K^\bullet : D(E, \text{d}) \longrightarrow D_\mathit{QCoh}(\mathcal{O}_ X)

and by our choice of K^\bullet as a generator of D_\mathit{QCoh}(\mathcal{O}_ X) the kernel of the adjoint restricted to D_\mathit{QCoh}(\mathcal{O}_ X) is zero. A formal argument shows that we obtain the desired equivalence, see Derived Categories, Lemma 13.7.2. \square

Remark 36.18.3 (Variant with support). Let X be a quasi-compact and quasi-separated scheme. Let T \subset X be a closed subset such that X \setminus T is quasi-compact. The analogue of Theorem 36.18.2 holds for D_{\mathit{QCoh}, T}(\mathcal{O}_ X). This follows from the exact same argument as in the proof of the theorem, using Lemmas 36.15.4 and 36.17.3 and a variant of Lemma 36.18.1 with supports. If we ever need this, we will precisely state the result here and give a detailed proof.

Remark 36.18.4 (Uniqueness of dga). Let X be a quasi-compact and quasi-separated scheme over a ring R. By the construction of the proof of Theorem 36.18.2 there exists a differential graded algebra (A, \text{d}) over R such that D_\mathit{QCoh}(X) is R-linearly equivalent to D(A, \text{d}) as a triangulated category. One may ask: how unique is (A, \text{d})? The answer is (only) slightly better than just saying that (A, \text{d}) is well defined up to derived equivalence. Namely, suppose that (B, \text{d}) is a second such pair. Then we have

(A, \text{d}) = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(K^\bullet , K^\bullet )

and

(B, \text{d}) = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(L^\bullet , L^\bullet )

for some K-injective complexes K^\bullet and L^\bullet of \mathcal{O}_ X-modules corresponding to perfect generators of D_\mathit{QCoh}(\mathcal{O}_ X). Set

\Omega = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(K^\bullet , L^\bullet ) \quad \Omega ' = \mathop{\mathrm{Hom}}\nolimits _{\text{Comp}^{dg}(\mathcal{O}_ X)}(L^\bullet , K^\bullet )

Then \Omega is a differential graded B^{opp} \otimes _ R A-module and \Omega ' is a differential graded A^{opp} \otimes _ R B-module. Moreover, the equivalence

D(A, \text{d}) \to D_\mathit{QCoh}(\mathcal{O}_ X) \to D(B, \text{d})

is given by the functor - \otimes _ A^\mathbf {L} \Omega ' and similarly for the quasi-inverse. Thus we are in the situation of Differential Graded Algebra, Remark 22.37.10. If we ever need this remark we will provide a precise statement with a detailed proof here.


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.