Loading web-font TeX/Math/Italic

The Stacks project

Lemma 87.10.4. Let S be a scheme. Let X be a presheaf on (\mathit{Sch}/S)_{fppf}. The following are equivalent

  1. X is a countably indexed affine formal algebraic space,

  2. X = \text{Spf}(A) where A is a weakly admissible topological S-algebra which has a countable fundamental system of neighbourhoods of 0,

  3. X = \text{Spf}(A) where A is a weakly admissible topological S-algebra which has a fundamental system A \supset I_1 \supset I_2 \supset I_3 \supset \ldots of weak ideals of definition,

  4. X = \text{Spf}(A) where A is a complete topological S-algebra with a fundamental system of open neighbourhoods of 0 given by a countable sequence A \supset I_1 \supset I_2 \supset I_3 \supset \ldots of ideals such that I_ n/I_{n + 1} is locally nilpotent, and

  5. X = \text{Spf}(A) where A = \mathop{\mathrm{lim}}\nolimits B/J_ n with the limit topology where B \supset J_1 \supset J_2 \supset J_3 \supset \ldots is a sequence of ideals in an S-algebra B with J_ n/J_{n + 1} locally nilpotent.

Proof. Assume (1). By Lemma 87.10.3 we can write X = \text{Spf}(A) where A is a weakly admissible topological S-algebra. For any presentation X = \mathop{\mathrm{colim}}\nolimits X_ n as in Lemma 87.10.1 part (1) we see that A = \mathop{\mathrm{lim}}\nolimits A_ n with X_ n = \mathop{\mathrm{Spec}}(A_ n) and A_ n = A/I_ n for some weak ideal of definition I_ n \subset A. This follows from the final statement of Lemma 87.9.6 which moreover implies that \{ I_ n\} is a fundamental system of open neighbourhoods of 0. Thus we have a sequence

A \supset I_1 \supset I_2 \supset I_3 \supset \ldots

of weak ideals of definition with A = \mathop{\mathrm{lim}}\nolimits A/I_ n. In this way we see that condition (1) implies each of the conditions (2) – (5).

Assume (5). First note that the limit topology on A = \mathop{\mathrm{lim}}\nolimits B/J_ n is a linearly topologized, complete topology, see More on Algebra, Section 15.36. If f \in A maps to zero in B/J_1, then some power maps to zero in B/J_2 as its image in J_1/J_2 is nilpotent, then a further power maps to zero in J_2/J_3, etc, etc. In this way we see the open ideal \mathop{\mathrm{Ker}}(A \to B/J_1) is a weak ideal of definition. Thus A is weakly admissible. In this way we see that (5) implies (2).

It is clear that (4) is a special case of (5) by taking B = A. It is clear that (3) is a special case of (2).

Assume A is as in (2). Let E_ n be a countable fundamental system of neighbourhoods of 0 in A. Since A is a weakly admissible topological ring we can find open ideals I_ n \subset E_ n. We can also choose a weak ideal of definition J \subset A. Then J \cap I_ n is a fundamental system of weak ideals of definition of A and we get X = \text{Spf}(A) = \mathop{\mathrm{colim}}\nolimits \mathop{\mathrm{Spec}}(A/(J \cap I_ n)) which shows that X is a countably indexed affine formal algebraic space. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.