Lemma 87.29.8. Let S be a scheme. Let f : X \to Y be a morphism of affine formal algebraic spaces. Assume Y countably indexed. The following are equivalent
Proof. Since X and Y are affine it is clear that conditions (1) and (2) are equivalent. In cases (1) and (2) the morphism f is representable by algebraic spaces by definition, hence affine by Lemma 87.19.7. Thus if (1) or (2) holds we see that X is countably indexed by Lemma 87.19.9. Write X = \text{Spf}(A) and Y = \text{Spf}(B) for topological S-algebras A and B in \textit{WAdm}^{count}, see Lemma 87.10.4. By Lemma 87.9.10 we see that f corresponds to a continuous map B \to A. Hence now the result follows from Lemma 87.29.2. \square
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