Processing math: 100%

The Stacks project

Lemma 15.75.7. Let R be a ring. Let \mathfrak p \subset R be a prime. Let K \in D(R) be perfect. Set d_ i = \dim _{\kappa (\mathfrak p)} H^ i(K \otimes _ R^\mathbf {L} \kappa (\mathfrak p)). Then d_ i < \infty and only a finite number are nonzero. Then there exists an f \in R, f \not\in \mathfrak p and a complex

\ldots \to 0 \to R_ f^{\oplus d_ a} \to R_ f^{\oplus d_{a + 1}} \to \ldots \to R_ f^{\oplus d_{b - 1}} \to R_ f^{\oplus d_ b} \to 0 \to \ldots

representing K \otimes _ R^\mathbf {L} R_ f in D(R_ f).

Proof. Observe that K \otimes _ R^\mathbf {L} \kappa (\mathfrak p) is perfect as an object of D(\kappa (\mathfrak p)), see Lemma 15.74.9. Hence only a finite number of d_ i are nonzero and they are all finite. Applying Lemma 15.75.6 we get a complex representing K having the desired shape over the local ring R_\mathfrak p. We have R_\mathfrak p = \mathop{\mathrm{colim}}\nolimits R_ f for f \in R, f \not\in \mathfrak p (Algebra, Lemma 10.9.9). We conclude by Lemma 15.74.17. Some details omitted. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.