Lemma 49.2.9. Let A \to B be a flat quasi-finite homomorphism of Noetherian rings. Then \omega _{B/A} is a flat A-module.
Proof. Let \mathfrak q \subset B be a prime lying over \mathfrak p \subset A. We will show that the localization \omega _{B/A, \mathfrak q} is flat over A_\mathfrak p. This suffices by Algebra, Lemma 10.39.18. By Algebra, Lemma 10.145.2 we can find an étale ring map A \to A' and a prime ideal \mathfrak p' \subset A' lying over \mathfrak p such that \kappa (\mathfrak p') = \kappa (\mathfrak p) and such that
with A' \to C finite and such that the unique prime \mathfrak q' of B \otimes _ A A' lying over \mathfrak q and \mathfrak p' corresponds to a prime of C. By Lemma 49.2.5 and Algebra, Lemma 10.100.1 it suffices to show \omega _{B'/A', \mathfrak q'} is flat over A'_{\mathfrak p'}. Since \omega _{B'/A'} = \omega _{C/A'} \times \omega _{D/A'} by Lemma 49.2.7 this reduces us to the case where B is finite flat over A. In this case B is finite locally free as an A-module and \omega _{B/A} = \mathop{\mathrm{Hom}}\nolimits _ A(B, A) is the dual finite locally free A-module. \square
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