Lemma 55.11.8. In Situation 55.9.3 assume X is a minimal model, \gcd (m_1, \ldots , m_ n) = 1, and H^0((X_ k)_{red}, \mathcal{O}) = k. Then the map
is surjective and has a nontrivial kernel as soon as (X_ k)_{red} \not= X_ k.
Lemma 55.11.8. In Situation 55.9.3 assume X is a minimal model, \gcd (m_1, \ldots , m_ n) = 1, and H^0((X_ k)_{red}, \mathcal{O}) = k. Then the map
is surjective and has a nontrivial kernel as soon as (X_ k)_{red} \not= X_ k.
Proof. By vanishing of cohomology in degrees \geq 2 over X_ k (Cohomology, Proposition 20.20.7) any surjection of abelian sheaves on X_ k induces a surjection on H^1. Consider the sequence
of Lemma 55.9.9. Since the field maps H^0(Z_ j, \mathcal{O}_{Z_ j}) \to H^0((X_ k)_{red}, \mathcal{O}_{(X_ k)_{red}}) = k are injective we conclude that H^0(Z_ j, \mathcal{O}_{Z_ j}) = k for j = 0, \ldots , m. It follows that H^0(X_ k, \mathcal{O}_{X_ k}) \to H^0(Z_{m - 1}, \mathcal{O}_{Z_{m - 1}}) is surjective. Let C = C_{i_ m}. Then X_ k = Z_{m - 1} + C. Let \mathcal{L} = \mathcal{O}_ X(-Z_{m - 1})|_ C. Then \mathcal{L} is an invertible \mathcal{O}_ C-module. As in the proof of Lemma 55.9.9 there is an exact sequence
of coherent sheaves on X_ k. We conclude that we get a short exact sequence
The degree of \mathcal{L} on C over k is
Set \kappa = H^0(C, \mathcal{O}_ C) and w = [\kappa : k]. By definition of the degree of an invertible sheaf we see that
where g_ C is the genus of C. This expression is < 0 as X is minimal and hence C is not an exceptional curve of the first kind (see proof of Lemma 55.11.5). Thus \dim _ k H^1(C, \mathcal{L}) > 0 which finishes the proof. \square
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Comment #2949 by Maciek Zdanowicz on
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