Lemma 76.48.9. The property \mathcal{P}(f) =“f is a local complete intersection morphism” is fpqc local on the base.
Proof. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Let \{ Y_ i \to Y\} be an fpqc covering (Topologies on Spaces, Definition 73.9.1). Let f_ i : X_ i \to Y_ i be the base change of f by Y_ i \to Y. If f is a local complete intersection morphism, then each f_ i is a local complete intersection morphism by Lemma 76.48.4.
Conversely, assume each f_ i is a local complete intersection morphism. We may replace the covering by a refinement (again because flat base change preserves the property of being a local complete intersection morphism). Hence we may assume Y_ i is a scheme for each i, see Topologies on Spaces, Lemma 73.9.5. Choose a scheme V and a surjective étale morphism V \to Y. Choose a scheme U and a surjective étale morphism U \to V \times _ Y X. We have to show that U \to V is a local complete intersection morphism of schemes. By Topologies on Spaces, Lemma 73.9.4 we have that \{ Y_ i \times _ Y V \to V\} is an fpqc covering of schemes. By the case of schemes (More on Morphisms, Lemma 37.62.19) it suffices to prove the base change
of U \to V by V \times _ Y Y_ i \to V is a local complete intersection morphism. We can write this as the composition
The first arrow is an étale morphism of schemes (as a base change of U \to V \times _ Y X) and the second arrow is a local complete intersection morphism of schemes as a flat base change of f_ i. The result follows as being a local complete intersection morphism is syntomic local on the source and since étale morphisms are syntomic (More on Morphisms, Lemma 37.62.20 and Morphisms, Lemma 29.36.10). \square
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