Lemma 37.71.3. Let (R, I) be a pair consisting of a ring and an ideal I contained in the Jacobson radical. Set S = \mathop{\mathrm{Spec}}(R) and S_0 = \mathop{\mathrm{Spec}}(R/I). Let f : X \to S be proper, flat, and of finite presentation. Denote X_0 = S_0 \times _ S X. Let E \in D(\mathcal{O}_ X) be pseudo-coherent. If the derived restriction E_0 of E to X_0 is S_0-perfect, then E is S-perfect.
Proof. Choose a finite affine open covering X = U_1 \cup \ldots \cup U_ n. For each i we can choose a closed immersion U_ i \to \mathbf{A}^{d_ i}_ S. Set U_{i, 0} = S_0 \times _ S U_ i. For each i the complex E_0|_{U_{i, 0}} has tor amplitude in [a_ i, b_ i] for some a_ i, b_ i \in \mathbf{Z}. Let x \in X be a point. We will show that the tor amplitude of E_ x over R is in [a_ i - d_ i, b_ i] for some i. This will finish the proof as the tor amplitude can be read off from the stalks by Cohomology, Lemma 20.48.5.
Since f is proper f(\overline{\{ x\} }) is a closed subset of S. Since I is contained in the Jacobson radical, we see that f(\overline{\{ x\} }) meeting the closed subset S_0 \subset S. Hence there is a specialization x \leadsto x_0 with x_0 \in X_0. Pick an i with x_0 \in U_ i, so x_0 \in U_{i, 0}. We will fix i for the rest of the proof. Write U_ i = \mathop{\mathrm{Spec}}(A). Then A is a flat, finitely presented R-algebra which is a quotient of a polynomial R-algebra in d_ i-variables. The restriction E|_{U_ i} corresponds (by Derived Categories of Schemes, Lemma 36.3.5 and 36.10.2) to a pseudo-coherent object K of D(A). Observe that E_0 corresponds to K \otimes _ A^\mathbf {L} A/IA. Let \mathfrak q \subset \mathfrak q_0 \subset A be the prime ideals corresponding to x \leadsto x_0. Then E_ x = K_{\mathfrak q} and K_{\mathfrak q} is a localization of K_{\mathfrak q_0}. Hence it suffices to show that K_{\mathfrak q_0} has tor amplitude in [a_ i - d_ i, b_ i] as a complex of R-modules. Let I \subset \mathfrak p_0 \subset R be the prime ideal corresponding to f(x_0). Then we have
the second equality because R \to A is flat. By our choice of a_ i, b_ i this complex has cohomology only in degrees in the interval [a_ i, b_ i]. Thus we may finally apply More on Algebra, Lemma 15.83.9 to R \to A, \mathfrak q_0, \mathfrak p_0 and K to conclude. \square
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