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The Stacks project

Lemma 87.4.6. Let R be a topological ring. Let M be a topological R-module. Let I \subset R be a finitely generated ideal. Assume M has an open submodule whose topology is I-adic. Then M^\wedge has an open submodule whose topology is I-adic and we have M^\wedge /I^ n M^\wedge = M/I^ nM for all n \geq 1.

Proof. Let M' \subset M be an open submodule whose topology is I-adic. Then \{ I^ nM'\} _{n \geq 1} is a fundamental system of open submodules of M. Thus M^\wedge = \mathop{\mathrm{lim}}\nolimits M/I^ nM' contains (M')^\wedge = \mathop{\mathrm{lim}}\nolimits M'/I^ nM' as an open submodule and the topology on (M')^\wedge is I-adic by Algebra, Lemma 10.96.3. Since I is finitely generated, I^ n is finitely generated, say by f_1, \ldots , f_ r. Observe that the surjection (f_1, \ldots , f_ r) : M^{\oplus r} \to I^ n M is continuous and open by our description of the topology on M above. By Lemma 87.4.5 applied to this surjection and to the short exact sequence 0 \to I^ nM \to M \to M/I^ nM \to 0 we conclude that

(f_1, \ldots , f_ r) : (M^\wedge )^{\oplus r} \longrightarrow M^\wedge

surjects onto the kernel of the surjection M^\wedge \to M/I^ nM. Since f_1, \ldots , f_ r generate I^ n we conclude. \square


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