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63.6 Upper shriek for locally quasi-finite morphisms

For a locally quasi-finite morphism f : X \to Y of schemes, the functor f_! : \textit{Ab}(X_{\acute{e}tale}) \to \textit{Ab}(Y_{\acute{e}tale}) commutes with direct sums and is exact, see Lemma 63.4.5. This suggests that it has a right adjoint which we will denote f^!.

Warning: This functor is the non-derived version!

Lemma 63.6.1. Let f : X \to Y be a locally quasi-finite morphism of schemes.

  1. The functor f_! : \textit{Ab}(X_{\acute{e}tale}) \to \textit{Ab}(Y_{\acute{e}tale}) has a right adjoint f^! : \textit{Ab}(Y_{\acute{e}tale}) \to \textit{Ab}(X_{\acute{e}tale}).

  2. We have f^!(\overline{y}_*A) = \prod _{f(\overline{x}) = \overline{y}} \overline{x}_*A.

  3. If \Lambda is a ring, then the functor f_! : \textit{Mod}(X_{\acute{e}tale}, \Lambda ) \to \textit{Mod}(Y_{\acute{e}tale}, \Lambda ) has a right adjoint f^! : \textit{Mod}(Y_{\acute{e}tale}, \Lambda ) \to \textit{Mod}(X_{\acute{e}tale}, \Lambda ) which agrees with f^! on underlying abelian sheaves.

Proof. Proof of (1). Let E \subset \mathop{\mathrm{Ob}}\nolimits (\textit{Ab}(Y_{\acute{e}tale})) be the class consisting of products of skyscraper sheaves. We claim that

  1. every \mathcal{G} in \textit{Ab}(Y_{\acute{e}tale}) is a subsheaf of an element of E, and

  2. for every \mathcal{G} \in E there exists an object \mathcal{H} of \textit{Ab}(X_{\acute{e}tale}) such that \mathop{\mathrm{Hom}}\nolimits (f_!\mathcal{F}, \mathcal{G}) = \mathop{\mathrm{Hom}}\nolimits (\mathcal{F}, \mathcal{H}) functorially in \mathcal{F}.

Once the claim has been verified, the dual of Homology, Lemma 12.29.6 produces the adjoint functor f^!.

Part (a) is true because we can map \mathcal{G} to the sheaf \prod \overline{y}_*\mathcal{G}_{\overline{y}} where the product is over all geometric points of Y. This is an injection by Étale Cohomology, Theorem 59.29.10. (This is the first step in the Godement resolution when done in the setting of abelian sheaves on topological spaces.)

Part (b) and part (2) of the lemma can be seen as follows. Suppose that \mathcal{G} = \prod \overline{y}_*A_{\overline{y}} for some abelian groups A_{\overline{y}}. Then

\mathop{\mathrm{Hom}}\nolimits (f_!\mathcal{F}, \mathcal{G}) = \prod \mathop{\mathrm{Hom}}\nolimits (f_!\mathcal{F}, \overline{y}_*A_{\overline{y}})

Thus it suffices to find abelian sheaves \mathcal{H}_{\overline{y}} on X_{\acute{e}tale} representing the functors \mathcal{F} \mapsto \mathop{\mathrm{Hom}}\nolimits (f_!\mathcal{F}, \overline{y}_*A_{\overline{y}}) and to take \mathcal{H} = \prod \mathcal{H}_{\overline{y}}. This reduces us to the case \mathcal{H} = \overline{y}_*A for some fixed geometric point \overline{y} : \mathop{\mathrm{Spec}}(k) \to Y and some fixed abelian group A. We claim that in this case \mathcal{H} = \prod _{f(\overline{x}) = \overline{y}} \overline{x}_*A works. This will finish the proof of parts (1) and (2) of the lemma. Namely, we have

\mathop{\mathrm{Hom}}\nolimits (f_!\mathcal{F}, \overline{y}_*A) = \mathop{\mathrm{Hom}}\nolimits _{\textit{Ab}}((f_!\mathcal{F})_{\overline{y}}, A) = \mathop{\mathrm{Hom}}\nolimits _{\textit{Ab}}(\bigoplus \nolimits _{f(\overline{x}) = \overline{y}} \mathcal{F}_{\overline{x}}, A)

by the description of stalks in Lemma 63.4.5 on the one hand and on the other hand we have

\mathop{\mathrm{Hom}}\nolimits (\mathcal{F}, \mathcal{H}) = \prod \nolimits _{f(\overline{x}) = \overline{y}} \mathop{\mathrm{Hom}}\nolimits (\mathcal{F}, \overline{x}_*A) = \prod \nolimits _{f(\overline{x}) = \overline{y}} \mathop{\mathrm{Hom}}\nolimits _{\textit{Ab}}(\mathcal{F}_{\overline{x}}, A)

We leave it to the reader to identify these as functors of \mathcal{F}.

Proof of part (3). Observe that an object \textit{Mod}(X_{\acute{e}tale}, \Lambda ) is the same thing as an object \mathcal{F} of \textit{Ab}(X_{\acute{e}tale}) together with a map \Lambda \to \text{End}(\mathcal{F}). Hence the functors f_! and f^! in (1) define functors f_! and f^! as in (3). A straightforward computation shows that they are adjoints. \square

Lemma 63.6.2. Let j : U \to X be an étale morphism. Then j^! = j^{-1}.

Proof. This is true because j_! as defined in Section 63.4 agrees with j_! as defined in Étale Cohomology, Section 59.70, see Lemma 63.4.3. Finally, in Étale Cohomology, Section 59.70 the functor j_! is defined as the left adjoint of j^{-1} and hence we conclude by uniqueness of adjoint functors. \square

Lemma 63.6.3. Let f : X \to Y and g : Y \to Z be separated and locally quasi-finite morphisms. There is a canonical isomorphism (g \circ f)^! \to f^! \circ g^!. Given a third locally quasi-finite morphism h : Z \to T the diagram

\xymatrix{ (h \circ g \circ f)^! \ar[r] \ar[d] & f^! \circ (h \circ g)^! \ar[d] \\ (g \circ f)^! \circ h^! \ar[r] & f^! \circ g^! \circ h^! }

commutes.

Proof. By uniqueness of adjoint functors, this immediately translates into the corresponding (dual) statement for the functors f_!. See Lemma 63.4.12. \square

Lemma 63.6.4. Let j : U \to X and j' : V \to U be étale morphisms. The isomorphism (j \circ j')^{-1} = (j')^{-1} \circ j^{-1} and the isomorphism (j \circ j')^! = (j')^! \circ j^! of Lemma 63.6.3 agree via the isomorphism of Lemma 63.6.2.

Proof. Omitted. \square

Lemma 63.6.5. Consider a cartesian square

\xymatrix{ X' \ar[r]_{g'} \ar[d]_{f'} & X \ar[d]^ f \\ Y' \ar[r]^ g & Y }

of schemes with f locally quasi-finite. For any abelian sheaf \mathcal{F} on Y'_{\acute{e}tale} we have (g')_*(f')^!\mathcal{F} = f^!g_*\mathcal{F}.

Proof. By uniqueness of adjoint functors, this follows from the corresponding (dual) statement for the functors f_!. See Lemma 63.4.10. \square

Remark 63.6.6. The material in this section can be generalized to sheaves of pointed sets. Namely, for a site \mathcal{C} denote \mathop{\mathit{Sh}}\nolimits ^*(\mathcal{C}) the category of sheaves of pointed sets. The constructions in this and the preceding section apply, mutatis mutandis, to sheaves of pointed sets. Thus given a locally quasi-finite morphism f : X \to Y of schemes we obtain an adjoint pair of functors

f_! : \mathop{\mathit{Sh}}\nolimits ^*(X_{\acute{e}tale}) \longrightarrow \mathop{\mathit{Sh}}\nolimits ^*(Y_{\acute{e}tale}) \quad \text{and}\quad f^! : \mathop{\mathit{Sh}}\nolimits ^*(Y_{\acute{e}tale}) \longrightarrow \mathop{\mathit{Sh}}\nolimits ^*(X_{\acute{e}tale})

such that for every geometric point \overline{y} of Y there are isomorphisms

(f_!\mathcal{F})_{\overline{y}} = \coprod \nolimits _{f(\overline{x}) = \overline{y}} \mathcal{F}_{\overline{x}}

(coproduct taken in the category of pointed sets) functorial in \mathcal{F} \in \mathop{\mathit{Sh}}\nolimits ^*(X_{\acute{e}tale}) and isomorphisms

f^!(\overline{y}_*S) = \prod \nolimits _{f(\overline{x}) = \overline{y}} \overline{x}_*S

functorial in the pointed set S. If F : \textit{Ab}(X_{\acute{e}tale}) \to \mathop{\mathit{Sh}}\nolimits ^*(X_{\acute{e}tale}) and F : \textit{Ab}(Y_{\acute{e}tale}) \to \mathop{\mathit{Sh}}\nolimits ^*(Y_{\acute{e}tale}) denote the forgetful functors, compatibility between the constructions will guarantee the existence of canonical maps

f_!F(\mathcal{F}) \longrightarrow F(f_!\mathcal{F})

functorial in \mathcal{F} \in \textit{Ab}(X_{\acute{e}tale}) and

F(f^!\mathcal{G}) \longrightarrow f^!F(\mathcal{G})

functorial in \mathcal{G} \in \textit{Ab}(Y_{\acute{e}tale}) which produce the obvious maps on stalks, resp. skyscraper sheaves. In fact, the transformation F \circ f^! \to f^! \circ F is an isomorphism (because f^! commutes with products).


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