Proposition 50.14.1. Let X \to S be a morphism of schemes. Let \mathcal{E} be a locally free \mathcal{O}_ X-module of constant rank r. Consider the morphism p : P = \mathbf{P}(\mathcal{E}) \to X. Then the map
given by the rule
is an isomorphism.
The title says it all.
Proposition 50.14.1. Let X \to S be a morphism of schemes. Let \mathcal{E} be a locally free \mathcal{O}_ X-module of constant rank r. Consider the morphism p : P = \mathbf{P}(\mathcal{E}) \to X. Then the map
given by the rule
is an isomorphism.
Proof. Choose an affine open \mathop{\mathrm{Spec}}(A) \subset X such that \mathcal{E} restricts to the trivial locally free module \mathcal{O}_{\mathop{\mathrm{Spec}}(A)}^{\oplus r}. Then P \times _ X \mathop{\mathrm{Spec}}(A) = \mathbf{P}^{r - 1}_ A. Thus we see that p is proper and smooth, see Section 50.11. Moreover, the classes c_1^{dR}(\mathcal{O}_ P(1))^ i, i = 0, 1, \ldots , r - 1 restricted to a fibre X_ y = \mathbf{P}^{r - 1}_ y freely generate the de Rham cohomology H^*_{dR}(X_ y/y) over \kappa (y), see Lemma 50.11.4. Thus we've verified the conditions of Proposition 50.13.3 and we win. \square
Remark 50.14.2. In the situation of Proposition 50.14.1 we get moreover that the map
is an isomorphism in D(X, (X \to S)^{-1}\mathcal{O}_ X) as follows immediately from the application of Proposition 50.13.3. Note that the arrow for t = 0 is simply the canonical map c_{P/X} : \Omega ^\bullet _{X/S} \to Rp_*\Omega ^\bullet _{P/S} of Section 50.2. In fact, we can pin down this map further in this particular case. Namely, consider the canonical map
of Remark 50.4.3 corresponding to c_1^{dR}(\mathcal{O}_ P(1)). Then
is the map of Remark 50.4.3 corresponding to c_1^{dR}(\mathcal{O}_ P(1))^ t. Tracing through the choices made in the proof of Proposition 50.13.3 we find the value
for the restriction of our isomorphism to the summand \Omega ^\bullet _{X/S}[-2t]. This has the following simple consequence we will use below: let
viewed as subcomplexes of the source of the arrow \tilde\xi . It follows formally from the discussion above that
is an isomorphism and that the diagram
commutes where \text{id} : K \to M[2] identifies the summand corresponding to t in the deomposition of K to the summand corresponding to t + 1 in the decomposition of M.
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