The Stacks project

Lemma 20.52.2. Let $(X, \mathcal{O}_ X)$ be a ringed space. Let $M$ be an object of $D(\mathcal{O}_ X)$. The following are equivalent

  1. $M$ is invertible in $D(\mathcal{O}_ X)$, see Categories, Definition 4.43.4, and

  2. there is a locally finite direct product decomposition

    \[ \mathcal{O}_ X = \prod \nolimits _{n \in \mathbf{Z}} \mathcal{O}_ n \]

    and for each $n$ there is an invertible $\mathcal{O}_ n$-module $\mathcal{H}^ n$ (Modules, Definition 17.25.1) and $M = \bigoplus \mathcal{H}^ n[-n]$ in $D(\mathcal{O}_ X)$.

If (1) and (2) hold, then $M$ is a perfect object of $D(\mathcal{O}_ X)$. If $\mathcal{O}_{X, x}$ is a local ring for all $x \in X$ these condition are also equivalent to

  1. there exists an open covering $X = \bigcup U_ i$ and for each $i$ an integer $n_ i$ such that $M|_{U_ i}$ is represented by an invertible $\mathcal{O}_{U_ i}$-module placed in degree $n_ i$.

Proof. Assume (2). Consider the object $R\mathop{\mathcal{H}\! \mathit{om}}\nolimits (M, \mathcal{O}_ X)$ and the composition map

\[ R\mathop{\mathcal{H}\! \mathit{om}}\nolimits (M, \mathcal{O}_ X) \otimes _{\mathcal{O}_ X}^\mathbf {L} M \to \mathcal{O}_ X \]

To prove this is an isomorphism, we may work locally. Thus we may assume $\mathcal{O}_ X = \prod _{a \leq n \leq b} \mathcal{O}_ n$ and $M = \bigoplus _{a \leq n \leq b} \mathcal{H}^ n[-n]$. Then it suffices to show that

\[ R\mathop{\mathcal{H}\! \mathit{om}}\nolimits (\mathcal{H}^ m, \mathcal{O}_ X) \otimes _{\mathcal{O}_ X}^\mathbf {L} \mathcal{H}^ n \]

is zero if $n \not= m$ and equal to $\mathcal{O}_ n$ if $n = m$. The case $n \not= m$ follows from the fact that $\mathcal{O}_ n$ and $\mathcal{O}_ m$ are flat $\mathcal{O}_ X$-algebras with $\mathcal{O}_ n \otimes _{\mathcal{O}_ X} \mathcal{O}_ m = 0$. Using the local structure of invertible $\mathcal{O}_ X$-modules (Modules, Lemma 17.25.2) and working locally the isomorphism in case $n = m$ follows in a straightforward manner; we omit the details. Because $D(\mathcal{O}_ X)$ is symmetric monoidal, we conclude that $M$ is invertible.

Assume (1). The description in (2) shows that we have a candidate for $\mathcal{O}_ n$, namely, $\mathop{\mathcal{H}\! \mathit{om}}\nolimits _{\mathcal{O}_ X}(H^ n(M), H^ n(M))$. If this is a locally finite family of sheaves of rings and if $\mathcal{O}_ X = \prod \mathcal{O}_ n$, then we immediately obtain the direct sum decomposition $M = \bigoplus H^ n(M)[-n]$ using the idempotents in $\mathcal{O}_ X$ coming from the product decomposition. This shows that in order to prove (2) we may work locally on $X$.

Choose an object $N$ of $D(\mathcal{O}_ X)$ and an isomorphism $M \otimes _{\mathcal{O}_ X}^\mathbf {L} N \cong \mathcal{O}_ X$. Let $x \in X$. Then $N$ is a left dual for $M$ in the monoidal category $D(\mathcal{O}_ X)$ and we conclude that $M$ is perfect by Lemma 20.50.8. By symmetry we see that $N$ is perfect. After replacing $X$ by an open neighbourhood of $x$, we may assume $M$ and $N$ are represented by a strictly perfect complexes $\mathcal{E}^\bullet $ and $\mathcal{F}^\bullet $. Then $M \otimes _{\mathcal{O}_ X}^\mathbf {L} N$ is represented by $\text{Tot}(\mathcal{E}^\bullet \otimes _{\mathcal{O}_ X} \mathcal{F}^\bullet )$. After another shinking of $X$ we may assume the mutually inverse isomorphisms $\mathcal{O}_ X \to M \otimes _{\mathcal{O}_ X}^\mathbf {L} N$ and $M \otimes _{\mathcal{O}_ X}^\mathbf {L} N \to \mathcal{O}_ X$ are given by maps of complexes

\[ \alpha : \mathcal{O}_ X \to \text{Tot}(\mathcal{E}^\bullet \otimes _{\mathcal{O}_ X} \mathcal{F}^\bullet ) \quad \text{and}\quad \beta : \text{Tot}(\mathcal{E}^\bullet \otimes _{\mathcal{O}_ X} \mathcal{F}^\bullet ) \to \mathcal{O}_ X \]

See Lemma 20.46.8. Then $\beta \circ \alpha = 1$ as maps of complexes and $\alpha \circ \beta = 1$ as a morphism in $D(\mathcal{O}_ X)$. After shrinking $X$ we may assume the composition $\alpha \circ \beta $ is homotopic to $1$ by some homotopy $\theta $ with components

\[ \theta ^ n : \text{Tot}^ n(\mathcal{E}^\bullet \otimes _{\mathcal{O}_ X} \mathcal{F}^\bullet ) \to \text{Tot}^{n - 1}( \mathcal{E}^\bullet \otimes _{\mathcal{O}_ X} \mathcal{F}^\bullet ) \]

by the same lemma as before. Set $R = \Gamma (X, \mathcal{O}_ X)$. By Lemma 20.52.1 we find that we obtain

  1. $M^\bullet = \Gamma (X, \mathcal{E}^\bullet )$ is a bounded complex of finite projective $R$-modules,

  2. $N^\bullet = \Gamma (X, \mathcal{F}^\bullet )$ is a bounded complex of finite projective $R$-modules,

  3. $\alpha $ and $\beta $ correspond to maps of complexes $a : R \to \text{Tot}(M^\bullet \otimes _ R N^\bullet )$ and $b : \text{Tot}(M^\bullet \otimes _ R N^\bullet ) \to R$,

  4. $\theta ^ n$ corresponds to a map $h^ n : \text{Tot}^ n(M^\bullet \otimes _ R N^\bullet ) \to \text{Tot}^{n - 1}(M^\bullet \otimes _ R N^\bullet )$, and

  5. $b \circ a = 1$ and $b \circ a - 1 = dh + hd$,

It follows that $M^\bullet $ and $N^\bullet $ define mutually inverse objects of $D(R)$. By More on Algebra, Lemma 15.126.4 we find a product decomposition $R = \prod _{a \leq n \leq b} R_ n$ and invertible $R_ n$-modules $H^ n$ such that $M^\bullet \cong \bigoplus _{a \leq n \leq b} H^ n[-n]$. This isomorphism in $D(R)$ can be lifted to an morphism

\[ \bigoplus H^ n[-n] \longrightarrow M^\bullet \]

of complexes because each $H^ n$ is projective as an $R$-module. Correspondingly, using Lemma 20.52.1 again, we obtain an morphism

\[ \bigoplus H^ n \otimes _ R \mathcal{O}_ X[-n] \to \mathcal{E}^\bullet \]

which is an isomorphism in $D(\mathcal{O}_ X)$. Setting $\mathcal{O}_ n = R_ n \otimes _ R \mathcal{O}_ X$ we conclude (2) is true.

If all stalks of $\mathcal{O}_ X$ are local, then it is straightforward to prove the equivalence of (2) and (3). We omit the details. $\square$

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