Lemma 13.40.4. Let \mathcal{D} be a triangulated category. Let \mathcal{A} \subset \mathcal{D} be a full subcategory invariant under all shifts. Then both the right orthogonal \mathcal{A}^\perp and the left orthogonal {}^\perp \mathcal{A} of \mathcal{A} are strictly full, saturated1, triangulated subcagories of \mathcal{D}.
Proof. It is immediate from the definitions that the orthogonals are preserved under taking shifts, direct sums, and direct summands. Consider a distinguished triangle
X \to Y \to Z \to X[1]
of \mathcal{D}. By Lemma 13.4.16 it suffices to show that if X and Y are in \mathcal{A}^\perp , then Z is in \mathcal{A}^\perp . This is immediate from Lemma 13.40.2. \square
Comments (0)
There are also: