Lemma 88.4.5 (0GAM)—The Stacks project

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Table of contents
Part 5: Topics in Geometry
Chapter 88: Algebraization of Formal Spaces
Section 88.4: Rig-smooth algebras
Lemma 88.4.5 (cite)

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Lemma 88.4.5. Let $A_1 \to A_2$ be a map of Noetherian rings. Let $I_ i \subset A_ i$ be an ideal such that $V(I_1A_2) = V(I_2)$ . Let $B_1$ be in (88.2.0.2) for $(A_1, I_1)$ . Let $B_2$ be the base change of $B_1$ as in Remark 88.2.3. If $B_1$ is rig-smooth over $(A_1, I_1)$ , then $B_2$ is rig-smooth over $(A_2, I_2)$ .

Proof. Follows from Lemma 88.4.4 and Definition 88.4.1 and the fact that $I_2^ c$ is contained in $I_1A_2$ for some $c \geq 0$ as $A_2$ is Noetherian. $\square$

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