Lemma 29.13.6. A quasi-compact immersion is quasi-affine.
Proof. Let X \to S be a quasi-compact immersion. We have to show the inverse image of every affine open is quasi-affine. Hence, assuming S is an affine scheme, we have to show X is quasi-affine. By Lemma 29.7.7 the morphism X \to S factors as X \to Z \to S where Z is a closed subscheme of S and X \subset Z is a quasi-compact open. Since S is affine Lemma 29.2.1 implies Z is affine. Hence we win. \square
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