Proposition 36.8.5. In Situation 36.8.1. For every object $E$ of $D_\mathit{QCoh}(\mathcal{O}_ X)$ the map (36.8.4.1) is an isomorphism.

**Proof.**
By Lemma 36.3.5 we may assume that $E$ is given by a complex of quasi-coherent sheaves $\mathcal{F}^\bullet $. Let $M^\bullet = \Gamma (X, \mathcal{F}^\bullet )$ be the corresponding complex of $A$-modules. By Lemmas 36.8.3 and 36.8.4 we have quasi-isomorphisms

Taking $H^0$ on both sides we obtain

Since $\mathop{\mathrm{Hom}}\nolimits _{D(A)}(I^\bullet (f_1^ e, \ldots , f_ r^ e), M^\bullet ) = \mathop{\mathrm{Hom}}\nolimits _{D(\mathcal{O}_ X)}(I_ e, E)$ by Lemma 36.3.5 the lemma follows. $\square$

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