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The Stacks project

Lemma 36.10.6. Let X be a quasi-separated scheme. Let E be an object of D_\mathit{QCoh}(\mathcal{O}_ X). Let a \leq b. The following are equivalent

  1. E has tor amplitude in [a, b], and

  2. for all \mathcal{F} in \mathit{QCoh}(\mathcal{O}_ X) we have H^ i(E \otimes _{\mathcal{O}_ X}^\mathbf {L} \mathcal{F}) = 0 for i \not\in [a, b].

Proof. It is clear that (1) implies (2). Assume (2). Let U \subset X be an affine open. As X is quasi-separated the morphism j : U \to X is quasi-compact and separated, hence j_* transforms quasi-coherent modules into quasi-coherent modules (Schemes, Lemma 26.24.1). Thus the functor \mathit{QCoh}(\mathcal{O}_ X) \to \mathit{QCoh}(\mathcal{O}_ U) is essentially surjective. It follows that condition (2) implies the vanishing of H^ i(E|_ U \otimes _{\mathcal{O}_ U}^\mathbf {L} \mathcal{G}) for i \not\in [a, b] for all quasi-coherent \mathcal{O}_ U-modules \mathcal{G}. Write U = \mathop{\mathrm{Spec}}(A) and let M^\bullet be the complex of A-modules corresponding to E|_ U by Lemma 36.3.5. We have just shown that M^\bullet \otimes _ A^\mathbf {L} N has vanishing cohomology groups outside the range [a, b], in other words M^\bullet has tor amplitude in [a, b]. By Lemma 36.10.4 we conclude that E|_ U has tor amplitude in [a, b]. This proves the lemma. \square


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