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The Stacks project

Lemma 36.8.2. Let f : X \to Y be a morphism of Noetherian schemes. Then f_* on quasi-coherent sheaves has a right derived extension \Phi : D(\mathit{QCoh}(\mathcal{O}_ X)) \to D(\mathit{QCoh}(\mathcal{O}_ Y)) such that the diagram

\xymatrix{ D(\mathit{QCoh}(\mathcal{O}_ X)) \ar[d]_{\Phi } \ar[r] & D_\mathit{QCoh}(\mathcal{O}_ X) \ar[d]^{Rf_*} \\ D(\mathit{QCoh}(\mathcal{O}_ Y)) \ar[r] & D_\mathit{QCoh}(\mathcal{O}_ Y) }

commutes.

Proof. Since X and Y are Noetherian schemes the morphism is quasi-compact and quasi-separated (see Properties, Lemma 28.5.4 and Schemes, Remark 26.21.18). Thus f_* preserve quasi-coherence, see Schemes, Lemma 26.24.1. Next, let K be an object of D(\mathit{QCoh}(\mathcal{O}_ X)). Since \mathit{QCoh}(\mathcal{O}_ X) is a Grothendieck abelian category (Properties, Proposition 28.23.4), we can represent K by a K-injective complex \mathcal{I}^\bullet such that each \mathcal{I}^ n is an injective object of \mathit{QCoh}(\mathcal{O}_ X), see Injectives, Theorem 19.12.6. Thus we see that the functor \Phi is defined by setting

\Phi (K) = f_*\mathcal{I}^\bullet

where the right hand side is viewed as an object of D(\mathit{QCoh}(\mathcal{O}_ Y)). To finish the proof of the lemma it suffices to show that the canonical map

f_*\mathcal{I}^\bullet \longrightarrow Rf_*\mathcal{I}^\bullet

is an isomorphism in D(\mathcal{O}_ Y). To see this by Lemma 36.4.2 it suffices to show that \mathcal{I}^ n is right f_*-acyclic for all n \in \mathbf{Z}. This is true because \mathcal{I}^ n is flasque by Lemma 36.8.1 and flasque modules are right f_*-acyclic by Cohomology, Lemma 20.12.5. \square


Comments (2)

Comment #8132 by Dennis Eriksson on

It says "This is true because f_∗ I^n is flasque", but I think there should be no direct image there.


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