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The Stacks project

Lemma 76.3.6. Let S be a scheme. Let f : X \to Y be a morphism of algebraic spaces over S. Assume

  1. f is locally of finite type,

  2. for every étale morphism V \to Y the map |X \times _ Y V| \to |V| is injective.

Then f is universally injective.

Proof. The question is étale local on Y by Morphisms of Spaces, Lemma 67.19.6. Hence we may assume that Y is a scheme. Then Y is in particular decent and by Decent Spaces, Lemma 68.18.9 we see that f is locally quasi-finite. Let y \in Y be a point and let X_ y be the scheme theoretic fibre. Assume X_ y is not empty. By Spaces over Fields, Lemma 72.10.8 we see that X_ y is a scheme which is locally quasi-finite over \kappa (y). Since |X_ y| \subset |X| is the fibre of |X| \to |Y| over y we see that X_ y has a unique point x. The same is true for X_ y \times _{\mathop{\mathrm{Spec}}(\kappa (y))} \mathop{\mathrm{Spec}}(k) for any finite separable extension k/\kappa (y) because we can realize k as the residue field at a point lying over y in an étale scheme over Y, see More on Morphisms, Lemma 37.35.2. Thus X_ y is geometrically connected, see Varieties, Lemma 33.7.11. This implies that the finite extension \kappa (x)/\kappa (y) is purely inseparable.

We conclude (in the case that Y is a scheme) that for every y \in Y either the fibre X_ y is empty, or (X_ y)_{red} = \mathop{\mathrm{Spec}}(\kappa (x)) with \kappa (y) \subset \kappa (x) purely inseparable. Hence f is radicial (some details omitted), whence universally injective by Lemma 76.3.2. \square


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