Lemma 76.4.1 (David Rydh). A flat monomorphism of algebraic spaces is representable by schemes.
Proof. Let f : X \to Y be a flat monomorphism of algebraic spaces. To prove f is representable, we have to show X \times _ Y V is a scheme for every scheme V mapping to Y. Since being a scheme is local (Properties of Spaces, Lemma 66.13.1), we may assume V is affine. Thus we may assume Y = \mathop{\mathrm{Spec}}(B) is an affine scheme. Next, we can assume that X is quasi-compact by replacing X by a quasi-compact open. The space X is separated as X \to X \times _{\mathop{\mathrm{Spec}}(B)} X is an isomorphism. Applying Limits of Spaces, Lemma 70.17.3 we reduce to the case where B is local, X \to \mathop{\mathrm{Spec}}(B) is a flat monomorphism, and there exists a point x \in X mapping to the closed point of \mathop{\mathrm{Spec}}(B). Then X \to \mathop{\mathrm{Spec}}(B) is surjective as generalizations lift along flat morphisms of separated algebraic spaces, see Decent Spaces, Lemma 68.7.4. Hence we see that \{ X \to \mathop{\mathrm{Spec}}(B)\} is an fpqc cover. Then X \to \mathop{\mathrm{Spec}}(B) is a morphism which becomes an isomorphism after base change by X \to \mathop{\mathrm{Spec}}(B). Hence it is an isomorphism by fpqc descent, see Descent on Spaces, Lemma 74.11.15. \square
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