Lemma 73.8.8. Let S be a scheme. Let f : Y \to X be a morphism of algebraic spaces over S. The functor
u : (\textit{Spaces}/Y)_{ph} \longrightarrow (\textit{Spaces}/X)_{ph}, \quad V/Y \longmapsto V/X
is cocontinuous, and has a continuous right adjoint
v : (\textit{Spaces}/X)_{ph} \longrightarrow (\textit{Spaces}/Y)_{ph}, \quad (U \to Y) \longmapsto (U \times _ X Y \to Y).
They induce the same morphism of topoi
f_{big} : \mathop{\mathit{Sh}}\nolimits ((\textit{Spaces}/Y)_{ph}) \longrightarrow \mathop{\mathit{Sh}}\nolimits ((\textit{Spaces}/X)_{ph})
We have f_{big}^{-1}(\mathcal{G})(U/Y) = \mathcal{G}(U/X). We have f_{big, *}(\mathcal{F})(U/X) = \mathcal{F}(U \times _ X Y/Y). Also, f_{big}^{-1} has a left adjoint f_{big!} which commutes with fibre products and equalizers.
Proof.
The functor u is cocontinuous, continuous, and commutes with fibre products and equalizers. Hence Sites, Lemmas 7.21.5 and 7.21.6 apply and we deduce the formula for f_{big}^{-1} and the existence of f_{big!}. Moreover, the functor v is a right adjoint because given U/T and V/X we have \mathop{\mathrm{Mor}}\nolimits _ X(u(U), V) = \mathop{\mathrm{Mor}}\nolimits _ Y(U, V \times _ X Y) as desired. Thus we may apply Sites, Lemmas 7.22.1 and 7.22.2 to get the formula for f_{big, *}.
\square
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