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The Stacks project

Lemma 82.23.2. In Situation 82.2.1 let X/B be good. Let (\mathcal{L}, s, i : D \to X) be as in Definition 82.22.1. The Gysin homomorphism factors through rational equivalence to give a map i^* : \mathop{\mathrm{CH}}\nolimits _{k + 1}(X) \to \mathop{\mathrm{CH}}\nolimits _ k(D).

Proof. Let \alpha \in Z_{k + 1}(X) and assume that \alpha \sim _{rat} 0. This means there exists a locally finite collection of integral closed subspaces W_ j \subset X of \delta -dimension k + 2 and f_ j \in R(W_ j)^* such that \alpha = \sum i_{j, *}\text{div}_{W_ j}(f_ j). Set X' = \coprod W_ i and consider the diagram

\xymatrix{ D' \ar[d]_ q \ar[r]_{i'} & X' \ar[d]^ p \\ D \ar[r]^ i & X }

of Remark 82.22.3. Since X' \to X is proper we see that i^*p_* = q_*(i')^* by Lemma 82.22.5. As we know that q_* factors through rational equivalence (Lemma 82.16.3), it suffices to prove the result for \alpha ' = \sum \text{div}_{W_ j}(f_ j) on X'. Clearly this reduces us to the case where X is integral and \alpha = \text{div}(f) for some f \in R(X)^*.

Assume X is integral and \alpha = \text{div}(f) for some f \in R(X)^*. If X = D, then we see that i^*\alpha is equal to c_1(\mathcal{L}) \cap \alpha . This is rationally equivalent to zero by Lemma 82.21.2. If D \not= X, then we see that i^*\text{div}_ X(f) is equal to c_1(\mathcal{O}_ D) \cap [D]_{n - 1} in \mathop{\mathrm{CH}}\nolimits _ k(D) by Lemma 82.23.1. Of course capping with c_1(\mathcal{O}_ D) is the zero map. \square


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