Lemma 21.33.4. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') and f' : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}''), \mathcal{O}'') be morphisms of ringed topoi. The relative cup product of Remark 21.19.7 is compatible with compositions in the sense that the diagram
\xymatrix{ R(f' \circ f)_*K \otimes _{\mathcal{O}''}^\mathbf {L} R(f' \circ f)_*L \ar@{=}[rr] \ar[d] & & Rf'_*Rf_*K \otimes _{\mathcal{O}''}^\mathbf {L} Rf'_*Rf_*L \ar[d] \\ R(f' \circ f)_*(K \otimes _\mathcal {O}^\mathbf {L} L) \ar@{=}[r] & Rf'_*Rf_*(K \otimes _\mathcal {O}^\mathbf {L} L) & Rf'_*(Rf_*K \otimes _{\mathcal{O}'}^\mathbf {L} Rf_*L) \ar[l] }
is commutative in D(\mathcal{O}'') for all K, L in D(\mathcal{O}).
Proof.
This is true because going around the diagram either way we obtain the map adjoint to the map
\begin{align*} & L(f' \circ f)^*\left(R(f' \circ f)_*K \otimes _{\mathcal{O}''}^\mathbf {L} R(f' \circ f)_*L\right) \\ & = L(f' \circ f)^*R(f' \circ f)_*K \otimes _\mathcal {O}^\mathbf {L} L(f' \circ f)^*R(f' \circ f)_*L) \\ & \to K \otimes _\mathcal {O}^\mathbf {L} L \end{align*}
in D(\mathcal{O}). To see this one uses that the composition of the counits like so
L(f' \circ f)^*R(f' \circ f)_* = Lf^* L(f')^* Rf'_* Rf_* \to Lf^* Rf_* \to \text{id}
is the counit for L(f' \circ f)^* and R(f' \circ f)_*. See Categories, Lemma 4.24.9.
\square
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