98.15 Axioms for functors
Let S be a scheme. Let F : (\mathit{Sch}/S)_{fppf}^{opp} \to \textit{Sets} be a functor. Denote \mathcal{X} = \mathcal{S}_ F the category fibred in sets associated to F, see Algebraic Stacks, Section 94.7. In this section we provide a translation between the material above as it applies to \mathcal{X}, to statements about F.
Let S be a locally Noetherian scheme. Let F : (\mathit{Sch}/S)_{fppf}^{opp} \to \textit{Sets} be a functor. Let k be a field of finite type over S. Let x_0 \in F(\mathop{\mathrm{Spec}}(k)). The associated predeformation category (98.3.0.2) corresponds to the functor
Recall that we do not distinguish between categories cofibred in sets over \mathcal{C}_\Lambda and functor \mathcal{C}_\Lambda \to \textit{Sets}, see Formal Deformation Theory, Remarks 90.5.2 (11). Given a transformation of functors a : F \to G, setting y_0 = a(x_0) we obtain a morphism
see (98.3.1.1). Lemma 98.3.2 tells us that if a : F \to G is formally smooth (in the sense of More on Morphisms of Spaces, Definition 76.13.1), then F_{k, x_0} \longrightarrow G_{k, y_0} is smooth as in Formal Deformation Theory, Remark 90.8.4.
Lemma 98.4.1 says that if Y' = Y \amalg _ X X' in the category of schemes over S where X \to X' is a thickening and X \to Y is affine, then the map
is a bijection, provided that F is an algebraic space. We say a general functor F satisfies the Rim-Schlessinger condition or we say F satisfies (RS) if given any pushout Y' = Y \amalg _ X X' where Y, X, X' are spectra of Artinian local rings of finite type over S, then
is a bijection. Thus every algebraic space satisfies (RS).
Lemma 98.6.1 says that given a functor F which satisfies (RS), then all F_{k, x_0} are deformation functors as in Formal Deformation Theory, Definition 90.16.8, i.e., they satisfy (RS) as in Formal Deformation Theory, Remark 90.16.5. In particular the tangent space
has the structure of a k-vector space by Formal Deformation Theory, Lemma 90.12.2.
Lemma 98.8.1 says that an algebraic space F locally of finite type over S gives rise to deformation functors F_{k, x_0} with finite dimensional tangent spaces TF_{k, x_0}.
A formal object1 \xi = (R, \xi _ n) of F consists of a Noetherian complete local S-algebra R whose residue field is of finite type over S, together with elements \xi _ n \in F(\mathop{\mathrm{Spec}}(R/\mathfrak m^ n)) such that \xi _{n + 1}|_{\mathop{\mathrm{Spec}}(R/\mathfrak m^ n)} = \xi _ n. A formal object \xi defines a formal object \xi of F_{R/\mathfrak m, \xi _1}. We say \xi is versal if and only if it is versal in the sense of Formal Deformation Theory, Definition 90.8.9. A formal object \xi = (R, \xi _ n) is called effective if there exists an x \in F(\mathop{\mathrm{Spec}}(R)) such that \xi _ n = x|_{\mathop{\mathrm{Spec}}(R/\mathfrak m^ n)} for all n \geq 1. Lemma 98.9.5 says that if F is an algebraic space, then every formal object is effective.
Let U be a scheme locally of finite type over S and let x \in F(U). Let u_0 \in U be a finite type point. We say that x is versal at u_0 if and only if \xi = (\mathcal{O}_{U, u_0}^\wedge , x|_{\mathop{\mathrm{Spec}}(\mathcal{O}_{U, u_0}/\mathfrak m_{u_0}^ n)}) is a versal formal object in the sense described above.
Let S be a locally Noetherian scheme. Let F : (\mathit{Sch}/S)_{fppf}^{opp} \to \mathit{Sch} be a functor. Here are the axioms we will consider on F.
a set theoretic condition2 to be ignored by readers who are not interested in set theoretical issues,
F is a sheaf for the étale topology,
F is limit preserving,
F satisfies the Rim-Schlessinger condition (RS),
every tangent space TF_{k, x_0} is finite dimensional,
every formal object is effective,
F satisfies openness of versality.
Here limit preserving is the notion defined in Limits of Spaces, Definition 70.3.1 and openness of versality means the following: Given a scheme U locally of finite type over S, given x \in F(U), and given a finite type point u_0 \in U such that x is versal at u_0, then there exists an open neighbourhood u_0 \in U' \subset U such that x is versal at every finite type point of U'.
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