The Stacks project

Lemma 28.22.9. Let $X$ be a quasi-compact and quasi-separated scheme. Let $\mathcal{F}$ be a finite type quasi-coherent $\mathcal{O}_ X$-module. Let $U \subset X$ be a quasi-compact open such that $\mathcal{F}|_ U$ is of finite presentation. Then there exists a map of $\mathcal{O}_ X$-modules $\varphi : \mathcal{G} \to \mathcal{F}$ with (a) $\mathcal{G}$ of finite presentation, (b) $\varphi $ is surjective, and (c) $\varphi |_ U$ is an isomorphism.

Proof. Write $\mathcal{F} = \mathop{\mathrm{colim}}\nolimits \mathcal{F}_ i$ as a directed colimit with each $\mathcal{F}_ i$ of finite presentation, see Lemma 28.22.7. Choose a finite affine open covering $X = \bigcup V_ j$ and choose finitely many sections $s_{jl} \in \mathcal{F}(V_ j)$ generating $\mathcal{F}|_{V_ j}$, see Lemma 28.16.1. By Sheaves, Lemma 6.29.1 we see that $s_{jl}$ is in the image of $\mathcal{F}_ i \to \mathcal{F}$ for $i$ large enough. Hence $\mathcal{F}_ i \to \mathcal{F}$ is surjective for $i$ large enough. Choose such an $i$ and let $\mathcal{K} \subset \mathcal{F}_ i$ be the kernel of the map $\mathcal{F}_ i \to \mathcal{F}$. Since $\mathcal{F}_ U$ is of finite presentation, we see that $\mathcal{K}|_ U$ is of finite type, see Modules, Lemma 17.11.3. Hence we can find a finite type quasi-coherent submodule $\mathcal{K}' \subset \mathcal{K}$ with $\mathcal{K}'|_ U = \mathcal{K}|_ U$, see Lemma 28.22.2. Then $\mathcal{G} = \mathcal{F}_ i/\mathcal{K}'$ with the given map $\mathcal{G} \to \mathcal{F}$ is a solution. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 080V. Beware of the difference between the letter 'O' and the digit '0'.