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The Stacks project

92.5 Constructing a resolution

In the Noetherian finite type case we can construct a “small” simplicial resolution for finite type ring maps.

Lemma 92.5.1. Let A be a Noetherian ring. Let A \to B be a finite type ring map. Let \mathcal{A} be the category of A-algebra maps C \to B. Let n \geq 0 and let P_\bullet be a simplicial object of \mathcal{A} such that

  1. P_\bullet \to B is a trivial Kan fibration of simplicial sets,

  2. P_ k is finite type over A for k \leq n,

  3. P_\bullet = \text{cosk}_ n \text{sk}_ n P_\bullet as simplicial objects of \mathcal{A}.

Then P_{n + 1} is a finite type A-algebra.

Proof. Although the proof we give of this lemma is straightforward, it is a bit messy. To clarify the idea we explain what happens for low n before giving the proof in general. For example, if n = 0, then (3) means that P_1 = P_0 \times _ B P_0. Since the ring map P_0 \to B is surjective, this is of finite type over A by More on Algebra, Lemma 15.5.1.

If n = 1, then (3) means that

P_2 = \{ (f_0, f_1, f_2) \in P_1^3 \mid d_0f_0 = d_0f_1,\ d_1f_0 = d_0f_2,\ d_1f_1 = d_1f_2 \}

where the equalities take place in P_0. Observe that the triple

(d_0f_0, d_1f_0, d_1f_1) = (d_0f_1, d_0f_2, d_1f_2)

is an element of the fibre product P_0 \times _ B P_0 \times _ B P_0 over B because the maps d_ i : P_1 \to P_0 are morphisms over B. Thus we get a map

\psi : P_2 \longrightarrow P_0 \times _ B P_0 \times _ B P_0

The fibre of \psi over an element (g_0, g_1, g_2) \in P_0 \times _ B P_0 \times _ B P_0 is the set of triples (f_0, f_1, f_2) of 1-simplices with (d_0, d_1)(f_0) = (g_0, g_1), (d_0, d_1)(f_1) = (g_0, g_2), and (d_0, d_1)(f_2) = (g_1, g_2). As P_\bullet \to B is a trivial Kan fibration the map (d_0, d_1) : P_1 \to P_0 \times _ B P_0 is surjective. Thus we see that P_2 fits into the cartesian diagram

\xymatrix{ P_2 \ar[d] \ar[r] & P_1^3 \ar[d] \\ P_0 \times _ B P_0 \times _ B P_0 \ar[r] & (P_0 \times _ B P_0)^3 }

By More on Algebra, Lemma 15.5.2 we conclude. The general case is similar, but requires a bit more notation.

The case n > 1. By Simplicial, Lemma 14.19.14 the condition P_\bullet = \text{cosk}_ n \text{sk}_ n P_\bullet implies the same thing is true in the category of simplicial A-algebras and hence in the category of sets (as the forgetful functor from A-algebras to sets commutes with limits). Thus

P_{n + 1} = \mathop{\mathrm{Mor}}\nolimits (\Delta [n + 1], P_\bullet ) = \mathop{\mathrm{Mor}}\nolimits (\text{sk}_ n \Delta [n + 1], \text{sk}_ n P_\bullet )

by Simplicial, Lemma 14.11.3 and Equation (14.19.0.1). We will prove by induction on 1 \leq k < m \leq n + 1 that the ring

Q_{k, m} = \mathop{\mathrm{Mor}}\nolimits (\text{sk}_ k \Delta [m], \text{sk}_ k P_\bullet )

is of finite type over A. The case k = 1, 1 < m \leq n + 1 is entirely similar to the discussion above in the case n = 1. Namely, there is a cartesian diagram

\xymatrix{ Q_{1, m} \ar[d] \ar[r] & P_1^ N \ar[d] \\ P_0 \times _ B \ldots \times _ B P_0 \ar[r] & (P_0 \times _ B P_0)^ N }

where N = {m + 1 \choose 2}. We conclude as before.

Let 1 \leq k_0 \leq n and assume Q_{k, m} is of finite type over A for all 1 \leq k \leq k_0 and k < m \leq n + 1. For k_0 + 1 < m \leq n + 1 we claim there is a cartesian square

\xymatrix{ Q_{k_0 + 1, m} \ar[d] \ar[r] & P_{k_0 + 1}^ N \ar[d] \\ Q_{k_0, m} \ar[r] & Q_{k_0, k_0 + 1}^ N }

where N is the number of nondegenerate (k_0 + 1)-simplices of \Delta [m]. Namely, to see this is true, think of an element of Q_{k_0 + 1, m} as a function f from the (k_0 + 1)-skeleton of \Delta [m] to P_\bullet . We can restrict f to the k_0-skeleton which gives the left vertical map of the diagram. We can also restrict to each nondegenerate (k_0 + 1)-simplex which gives the top horizontal arrow. Moreover, to give such an f is the same thing as giving its restriction to k_0-skeleton and to each nondegenerate (k_0 + 1)-face, provided these agree on the overlap, and this is exactly the content of the diagram. Moreover, the fact that P_\bullet \to B is a trivial Kan fibration implies that the map

P_{k_0} \to Q_{k_0, k_0 + 1} = \mathop{\mathrm{Mor}}\nolimits (\partial \Delta [k_0 + 1], P_\bullet )

is surjective as every map \partial \Delta [k_0 + 1] \to B can be extended to \Delta [k_0 + 1] \to B for k_0 \geq 1 (small argument about constant simplicial sets omitted). Since by induction hypothesis the rings Q_{k_0, m}, Q_{k_0, k_0 + 1} are finite type A-algebras, so is Q_{k_0 + 1, m} by More on Algebra, Lemma 15.5.2 once more. \square

Proposition 92.5.2. Let A be a Noetherian ring. Let A \to B be a finite type ring map. There exists a simplicial A-algebra P_\bullet with an augmentation \epsilon : P_\bullet \to B such that each P_ n is a polynomial algebra of finite type over A and such that \epsilon is a trivial Kan fibration of simplicial sets.

Proof. Let \mathcal{A} be the category of A-algebra maps C \to B. In this proof our simplicial objects and skeleton and coskeleton functors will be taken in this category.

Choose a polynomial algebra P_0 of finite type over A and a surjection P_0 \to B. As a first approximation we take P_\bullet = \text{cosk}_0(P_0). In other words, P_\bullet is the simplicial A-algebra with terms P_ n = P_0 \times _ A \ldots \times _ A P_0. (In the final paragraph of the proof this simplicial object will be denoted P^0_\bullet .) By Simplicial, Lemma 14.32.3 the map P_\bullet \to B is a trivial Kan fibration of simplicial sets. Also, observe that P_\bullet = \text{cosk}_0 \text{sk}_0 P_\bullet .

Suppose for some n \geq 0 we have constructed P_\bullet (in the final paragraph of the proof this will be P^ n_\bullet ) such that

  1. P_\bullet \to B is a trivial Kan fibration of simplicial sets,

  2. P_ k is a finitely generated polynomial algebra for 0 \leq k \leq n, and

  3. P_\bullet = \text{cosk}_ n \text{sk}_ n P_\bullet

By Lemma 92.5.1 we can find a finitely generated polynomial algebra Q over A and a surjection Q \to P_{n + 1}. Since P_ n is a polynomial algebra the A-algebra maps s_ i : P_ n \to P_{n + 1} lift to maps s'_ i : P_ n \to Q. Set d'_ j : Q \to P_ n equal to the composition of Q \to P_{n + 1} and d_ j : P_{n + 1} \to P_ n. We obtain a truncated simplicial object P'_\bullet of \mathcal{A} by setting P'_ k = P_ k for k \leq n and P'_{n + 1} = Q and morphisms d'_ i = d_ i and s'_ i = s_ i in degrees k \leq n - 1 and using the morphisms d'_ j and s'_ i in degree n. Extend this to a full simplicial object P'_\bullet of \mathcal{A} using \text{cosk}_{n + 1}. By functoriality of the coskeleton functors there is a morphism P'_\bullet \to P_\bullet of simplicial objects extending the given morphism of (n + 1)-truncated simplicial objects. (This morphism will be denoted P^{n + 1}_\bullet \to P^ n_\bullet in the final paragraph of the proof.)

Note that conditions (b) and (c) are satisfied for P'_\bullet with n replaced by n + 1. We claim the map P'_\bullet \to P_\bullet satisfies assumptions (1), (2), (3), and (4) of Simplicial, Lemmas 14.32.1 with n + 1 instead of n. Conditions (1) and (2) hold by construction. By Simplicial, Lemma 14.19.14 we see that we have P_\bullet = \text{cosk}_{n + 1}\text{sk}_{n + 1}P_\bullet and P'_\bullet = \text{cosk}_{n + 1}\text{sk}_{n + 1}P'_\bullet not only in \mathcal{A} but also in the category of A-algebras, whence in the category of sets (as the forgetful functor from A-algebras to sets commutes with all limits). This proves (3) and (4). Thus the lemma applies and P'_\bullet \to P_\bullet is a trivial Kan fibration. By Simplicial, Lemma 14.30.4 we conclude that P'_\bullet \to B is a trivial Kan fibration and (a) holds as well.

To finish the proof we take the inverse limit P_\bullet = \mathop{\mathrm{lim}}\nolimits P^ n_\bullet of the sequence of simplicial algebras

\ldots \to P^2_\bullet \to P^1_\bullet \to P^0_\bullet

constructed above. The map P_\bullet \to B is a trivial Kan fibration by Simplicial, Lemma 14.30.5. However, the construction above stabilizes in each degree to a fixed finitely generated polynomial algebra as desired. \square

Lemma 92.5.3. Let A be a Noetherian ring. Let A \to B be a finite type ring map. Let \pi , \underline{B} be as in (92.4.0.1). If \mathcal{F} is an \underline{B}-module such that \mathcal{F}(P, \alpha ) is a finite B-module for all \alpha : P = A[x_1, \ldots , x_ n] \to B, then the cohomology modules of L\pi _!(\mathcal{F}) are finite B-modules.

Proof. By Lemma 92.4.1 and Proposition 92.5.2 we can compute L\pi _!(\mathcal{F}) by a complex constructed out of the values of \mathcal{F} on finite type polynomial algebras. \square

Lemma 92.5.4. Let A be a Noetherian ring. Let A \to B be a finite type ring map. Then H^ n(L_{B/A}) is a finite B-module for all n \in \mathbf{Z}.

Remark 92.5.5 (Resolutions). Let A \to B be any ring map. Let us call an augmented simplicial A-algebra \epsilon : P_\bullet \to B a resolution of B over A if each P_ n is a polynomial algebra and \epsilon is a trivial Kan fibration of simplicial sets. If P_\bullet \to B is an augmentation of a simplicial A-algebra with each P_ n a polynomial algebra surjecting onto B, then the following are equivalent

  1. \epsilon : P_\bullet \to B is a resolution of B over A,

  2. \epsilon : P_\bullet \to B is a quasi-isomorphism on associated complexes,

  3. \epsilon : P_\bullet \to B induces a homotopy equivalence of simplicial sets.

To see this use Simplicial, Lemmas 14.30.8, 14.31.9, and 14.31.8. A resolution P_\bullet of B over A gives a cosimplicial object U_\bullet of \mathcal{C}_{B/A} as in Cohomology on Sites, Lemma 21.39.7 and it follows that

L\pi _!\mathcal{F} = \mathcal{F}(P_\bullet )

functorially in \mathcal{F}, see Lemma 92.4.1. The (formal part of the) proof of Proposition 92.5.2 shows that resolutions exist. We also have seen in the first proof of Lemma 92.4.2 that the standard resolution of B over A is a resolution (so that this terminology doesn't lead to a conflict). However, the argument in the proof of Proposition 92.5.2 shows the existence of resolutions without appealing to the simplicial computations in Simplicial, Section 14.34. Moreover, for any choice of resolution we have a canonical isomorphism

L_{B/A} = \Omega _{P_\bullet /A} \otimes _{P_\bullet , \epsilon } B

in D(B) by Lemma 92.4.3. The freedom to choose an arbitrary resolution can be quite useful.

Lemma 92.5.6. Let A \to B be a ring map. Let \pi , \mathcal{O}, \underline{B} be as in (92.4.0.1). For any \mathcal{O}-module \mathcal{F} we have

L\pi _!(\mathcal{F}) = L\pi _!(Li^*\mathcal{F}) = L\pi _!(\mathcal{F} \otimes _\mathcal {O}^\mathbf {L} \underline{B})

in D(\textit{Ab}).

Proof. It suffices to verify the assumptions of Cohomology on Sites, Lemma 21.39.12 hold for \mathcal{O} \to \underline{B} on \mathcal{C}_{B/A}. We will use the results of Remark 92.5.5 without further mention. Choose a resolution P_\bullet of B over A to get a suitable cosimplicial object U_\bullet of \mathcal{C}_{B/A}. Since P_\bullet \to B induces a quasi-isomorphism on associated complexes of abelian groups we see that L\pi _!\mathcal{O} = B. On the other hand L\pi _!\underline{B} is computed by \underline{B}(U_\bullet ) = B. This verifies the second assumption of Cohomology on Sites, Lemma 21.39.12 and we are done with the proof. \square

Lemma 92.5.7. Let A \to B be a ring map. Let \pi , \mathcal{O}, \underline{B} be as in (92.4.0.1). We have

L\pi _!(\mathcal{O}) = L\pi _!(\underline{B}) = B \quad \text{and}\quad L_{B/A} = L\pi _!(\Omega _{\mathcal{O}/A} \otimes _\mathcal {O} \underline{B}) = L\pi _!(\Omega _{\mathcal{O}/A})

in D(\textit{Ab}).

Proof. This is just an application of Lemma 92.5.6 (and the first equality on the right is Lemma 92.4.3). \square

Here is a special case of the fundamental triangle that is easy to prove.

Lemma 92.5.8. Let A \to B \to C be ring maps. If B is a polynomial algebra over A, then there is a distinguished triangle L_{B/A} \otimes _ B^\mathbf {L} C \to L_{C/A} \to L_{C/B} \to L_{B/A} \otimes _ B^\mathbf {L} C[1] in D(C).

Proof. We will use the observations of Remark 92.5.5 without further mention. Choose a resolution \epsilon : P_\bullet \to C of C over B (for example the standard resolution). Since B is a polynomial algebra over A we see that P_\bullet is also a resolution of C over A. Hence L_{C/A} is computed by \Omega _{P_\bullet /A} \otimes _{P_\bullet , \epsilon } C and L_{C/B} is computed by \Omega _{P_\bullet /B} \otimes _{P_\bullet , \epsilon } C. Since for each n we have the short exact sequence 0 \to \Omega _{B/A} \otimes _ B P_ n \to \Omega _{P_ n/A} \to \Omega _{P_ n/B} \to 0 (Algebra, Lemma 10.138.9) and since L_{B/A} = \Omega _{B/A}[0] (Lemma 92.4.7) we obtain the result. \square

Example 92.5.9. Let A \to B be a ring map. In this example we will construct an “explicit” resolution P_\bullet of B over A of length 2. To do this we follow the procedure of the proof of Proposition 92.5.2, see also the discussion in Remark 92.5.5.

We choose a surjection P_0 = A[u_ i] \to B where u_ i is a set of variables. Choose generators f_ t \in P_0, t \in T of the ideal \mathop{\mathrm{Ker}}(P_0 \to B). We choose P_1 = A[u_ i, x_ t] with face maps d_0 and d_1 the unique A-algebra maps with d_ j(u_ i) = u_ i and d_0(x_ t) = 0 and d_1(x_ t) = f_ t. The map s_0 : P_0 \to P_1 is the unique A-algebra map with s_0(u_ i) = u_ i. It is clear that

P_1 \xrightarrow {d_0 - d_1} P_0 \to B \to 0

is exact, in particular the map (d_0, d_1) : P_1 \to P_0 \times _ B P_0 is surjective. Thus, if P_\bullet denotes the 1-truncated simplicial A-algebra given by P_0, P_1, d_0, d_1, and s_0, then the augmentation \text{cosk}_1(P_\bullet ) \to B is a trivial Kan fibration. The next step of the procedure in the proof of Proposition 92.5.2 is to choose a polynomial algebra P_2 and a surjection

P_2 \longrightarrow \text{cosk}_1(P_\bullet )_2

Recall that

\text{cosk}_1(P_\bullet )_2 = \{ (g_0, g_1, g_2) \in P_1^3 \mid d_0(g_0) = d_0(g_1), d_1(g_0) = d_0(g_2), d_1(g_1) = d_1(g_2)\}

Thinking of g_ i \in P_1 as a polynomial in x_ t the conditions are

g_0(0) = g_1(0),\quad g_0(f_ t) = g_2(0),\quad g_1(f_ t) = g_2(f_ t)

Thus \text{cosk}_1(P_\bullet )_2 contains the elements y_ t = (x_ t, x_ t, f_ t) and z_ t = (0, x_ t, x_ t). Every element G in \text{cosk}_1(P_\bullet )_2 is of the form G = H + (0, 0, g) where H is in the image of A[u_ i, y_ t, z_ t] \to \text{cosk}_1(P_\bullet )_2. Here g \in P_1 is a polynomial with vanishing constant term such that g(f_ t) = 0 in P_0. Observe that

  1. g = x_ t x_{t'} - f_ t x_{t'} and

  2. g = \sum r_ t x_ t with r_ t \in P_0 if \sum r_ t f_ t = 0 in P_0

are elements of P_1 of the desired form. Let

Rel = \mathop{\mathrm{Ker}}(\bigoplus \nolimits _{t \in T} P_0 \longrightarrow P_0),\quad (r_ t) \longmapsto \sum r_ tf_ t

We set P_2 = A[u_ i, y_ t, z_ t, v_ r, w_{t, t'}] where r = (r_ t) \in Rel, with map

P_2 \longrightarrow \text{cosk}_1(P_\bullet )_2

given by y_ t \mapsto (x_ t, x_ t, f_ t), z_ t \mapsto (0, x_ t, x_ t), v_ r \mapsto (0, 0, \sum r_ t x_ t), and w_{t, t'} \mapsto (0, 0, x_ t x_{t'} - f_ t x_{t'}). A calculation (omitted) shows that this map is surjective. Our choice of the map displayed above determines the maps d_0, d_1, d_2 : P_2 \to P_1. Finally, the procedure in the proof of Proposition 92.5.2 tells us to choose the maps s_0, s_1 : P_1 \to P_2 lifting the two maps P_1 \to \text{cosk}_1(P_\bullet )_2. It is clear that we can take s_ i to be the unique A-algebra maps determined by s_0(x_ t) = y_ t and s_1(x_ t) = z_ t.


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