The Stacks project

58.27 Lefschetz for the fundamental group

Of course we have already proven a bunch of results of this type in the local case. In this section we discuss the projective case.

Proposition 58.27.1. Let $k$ be a field. Let $X$ be a proper scheme over $k$. Let $\mathcal{L}$ be an ample invertible $\mathcal{O}_ X$-module. Let $s \in \Gamma (X, \mathcal{L})$. Let $Y = Z(s)$ be the zero scheme of $s$. Assume that for all $x \in X \setminus Y$ we have

\[ \text{depth}(\mathcal{O}_{X, x}) + \dim (\overline{\{ x\} }) > 1 \]

Then the restriction functor $\textit{FÉt}_ X \to \textit{FÉt}_ Y$ is fully faithful. In fact, for any open subscheme $V \subset X$ containing $Y$ the restriction functor $\textit{FÉt}_ V \to \textit{FÉt}_ Y$ is fully faithful.

Proof. The first statement is a formal consequence of Lemma 58.17.6 and Algebraic and Formal Geometry, Proposition 52.28.1. The second statement follows from Lemma 58.17.6 and Algebraic and Formal Geometry, Lemma 52.28.2. $\square$

Proposition 58.27.2. Let $k$ be a field. Let $X$ be a proper scheme over $k$. Let $\mathcal{L}$ be an ample invertible $\mathcal{O}_ X$-module. Let $s \in \Gamma (X, \mathcal{L})$. Let $Y = Z(s)$ be the zero scheme of $s$. Let $\mathcal{V}$ be the set of open subschemes of $X$ containing $Y$ ordered by reverse inclusion. Assume that for all $x \in X \setminus Y$ we have

\[ \text{depth}(\mathcal{O}_{X, x}) + \dim (\overline{\{ x\} }) > 2 \]

Then the restriction functor

\[ \mathop{\mathrm{colim}}\nolimits _\mathcal {V} \textit{FÉt}_ V \to \textit{FÉt}_ Y \]

is an equivalence.

Proof. This is a formal consequence of Lemma 58.17.4 and Algebraic and Formal Geometry, Proposition 52.28.7. $\square$

Proposition 58.27.3. Let $k$ be a field. Let $X$ be a proper scheme over $k$. Let $\mathcal{L}$ be an ample invertible $\mathcal{O}_ X$-module. Let $s \in \Gamma (X, \mathcal{L})$. Let $Y = Z(s)$ be the zero scheme of $s$. Assume that for all $x \in X \setminus Y$ we have

\[ \text{depth}(\mathcal{O}_{X, x}) + \dim (\overline{\{ x\} }) > 2 \]

and that for $x \in X \setminus Y$ closed purity holds for $\mathcal{O}_{X, x}$. Then the restriction functor $\textit{FÉt}_ X \to \textit{FÉt}_ Y$ is an equivalence. If $X$ or equivalently $Y$ is connected, then

\[ \pi _1(Y, \overline{y}) \to \pi _1(X, \overline{y}) \]

is an isomorphism for any geometric point $\overline{y}$ of $Y$.

Proof. Fully faithfulness holds by Proposition 58.27.1. By Proposition 58.27.2 any object of $\textit{FÉt}_ Y$ is isomorphic to the fibre product $U \times _ V Y$ for some finite étale morphism $U \to V$ where $V \subset X$ is an open subscheme containing $Y$. The complement $T = X \setminus V$ is1 a finite set of closed points of $X \setminus Y$. Say $T = \{ x_1, \ldots , x_ n\} $. By assumption we can find finite étale morphisms $V'_ i \to \mathop{\mathrm{Spec}}(\mathcal{O}_{X, x_ i})$ agreeing with $U \to V$ over $V \times _ X \mathop{\mathrm{Spec}}(\mathcal{O}_{X, x_ i})$. By Limits, Lemma 32.20.1 applied $n$ times we see that $U \to V$ extends to a finite étale morphism $U' \to X$ as desired. See Lemma 58.8.1 for the final statement. $\square$

[1] Namely, $T$ is proper over $k$ (being closed in $X$) and affine (being closed in the affine scheme $X \setminus Y$, see Morphisms, Lemma 29.43.18) and hence finite over $k$ (Morphisms, Lemma 29.44.11). Thus $T$ is a finite set of closed points.

Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 0ELB. Beware of the difference between the letter 'O' and the digit '0'.