24.32 Miscellany
Let (f, f^\sharp ) : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') be a morphism of ringed topoi. Let \mathcal{A} be a sheaf of differential graded \mathcal{O}-algebras. Using the composition1
and the relative cup product (see Cohomology on Sites, Remark 21.19.7 and Section 21.33) we obtain a multiplication2
in D(\mathcal{O}'). This multiplication is associative in the sense that the diagram
commutes in D(\mathcal{O}'); this follows from Cohomology on Sites, Lemma 21.33.2. In exactly the same way, given a right differential graded \mathcal{A}-module \mathcal{M} we obtain a multiplication
in D(\mathcal{O}'). This multiplication is compatible with \mu above in the sense that the diagram
commutes in D(\mathcal{O}'); again this follows from Cohomology on Sites, Lemma 21.33.2.
A particular example of the above is when one takes f to be the morphism to the punctual topos \mathop{\mathit{Sh}}\nolimits (pt). In that case \mu is just the cup product map
and similarly \mu _\mathcal {M} is the cup product map
In general, via the identifications
of Cohomology on Sites, Remark 21.14.4 the map \mu _\mathcal {M} induces the cup product on cohomology. To see this use Cohomology on Sites, Lemma 21.33.4 where the second morphism of topoi is the morphism from \mathop{\mathit{Sh}}\nolimits (\mathcal{C}') to the punctual topos as above.
If \mathcal{M}_1 \to \mathcal{M}_2 is a homomorphism of right differential graded \mathcal{A}-modules, then the diagram
commutes in D(\mathcal{O}'); this follows from the fact that the relative cup product is functorial. Suppose we have a short exact sequence
of right differential graded \mathcal{A}-modules. Then we claim that the diagram
commutes in D(\mathcal{O}') where \delta : \mathcal{M}_3 \to \mathcal{M}_1[1] is the morphism of D(\mathcal{O}) coming from the given short exact sequence (see Derived Categories, Section 13.12). This is clear if our sequence is split as a sequence of graded right \mathcal{A}-modules, because in this case \delta can be represented by a map of right \mathcal{A}-modules and the discussion above applies. In general we argue using the cone on a and the diagram
where the right square is commutative in D(\mathcal{O}) by the definition of \delta in Derived Categories, Lemma 13.12.1. Now the cone C(a) has the structure of a right differential graded \mathcal{A}-module such that i, p, q are homomorphisms of right differential graded \mathcal{A}-modules, see Definition 24.22.2. Hence by the above we know that the corresponding diagrams commute for the morphisms q and -p. Since q is an isomorphism in D(\mathcal{O}) we conclude the same is true for \delta as desired.
In the situation above given a right differential graded \mathcal{A}-module \mathcal{M} let
In other words, \xi is a degree n cohomology class in the cohomology of \mathcal{M} viewed as a complex of \mathcal{O}-modules. By Lemma 24.29.9 we can construct maps
of right differential graded \mathcal{A}-modules where s is a quasi-isomorphism and such that \xi is the image of 1 \in H^0(\mathcal{C}, \mathcal{A}) via the morphism s[n]^{-1} \circ x in the derived category D(\mathcal{A}, \text{d}) and a fortiori in the derived category D(\mathcal{O}). It follows that the corresponding map
in D(\mathcal{O}) is uniquely characterized by the following two properties
\xi ' can be lifted to a morphism in D(\mathcal{A}, \text{d}), and
\xi = \xi '(1) in H^0(\mathcal{C}, \mathcal{M}[n]) = H^ n(\mathcal{C}, \mathcal{M}).
Using the compatibilities of x and s with the relative cup product discussed above it follows that for every3 morphism of ringed topoi (f, f^\sharp ) : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') the derived pushforward
of \xi ' is compatible with the maps \mu and \mu _{\mathcal{M}[n]} constructed above in the sense that the diagram
commutes in D(\mathcal{O}'). Using this compatibility for the map to the punctual topos, we see in particular that
commutes. Combined with \xi '(1) = \xi this implies that the induced map on cohomology
is given by left cup product by \xi as indicated.
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