Processing math: 100%

The Stacks project

21.28 Formalities on cohomological descent

In this section we discuss only to what extent a morphism of ringed topoi determines an embedding from the derived category downstairs to the derived category upstairs. Here is a typical result.

Lemma 21.28.1. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Consider the full subcategory D' \subset D(\mathcal{O}_\mathcal {D}) consisting of objects K such that

K \longrightarrow Rf_*Lf^*K

is an isomorphism. Then D' is a saturated triangulated strictly full subcategory of D(\mathcal{O}_\mathcal {D}) and the functor Lf^* : D' \to D(\mathcal{O}_\mathcal {C}) is fully faithful.

Proof. See Derived Categories, Definition 13.6.1 for the definition of saturated in this setting. See Derived Categories, Lemma 13.4.16 for a discussion of triangulated subcategories. The canonical map of the lemma is the unit of the adjoint pair of functors (Lf^*, Rf_*), see Lemma 21.19.1. Having said this the proof that D' is a saturated triangulated subcategory is omitted; it follows formally from the fact that Lf^* and Rf_* are exact functors of triangulated categories. The final part follows formally from fact that Lf^* and Rf_* are adjoint; compare with Categories, Lemma 4.24.4. \square

Lemma 21.28.2. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Consider the full subcategory D' \subset D(\mathcal{O}_\mathcal {C}) consisting of objects K such that

Lf^*Rf_*K \longrightarrow K

is an isomorphism. Then D' is a saturated triangulated strictly full subcategory of D(\mathcal{O}_\mathcal {C}) and the functor Rf_* : D' \to D(\mathcal{O}_\mathcal {D}) is fully faithful.

Proof. See Derived Categories, Definition 13.6.1 for the definition of saturated in this setting. See Derived Categories, Lemma 13.4.16 for a discussion of triangulated subcategories. The canonical map of the lemma is the counit of the adjoint pair of functors (Lf^*, Rf_*), see Lemma 21.19.1. Having said this the proof that D' is a saturated triangulated subcategory is omitted; it follows formally from the fact that Lf^* and Rf_* are exact functors of triangulated categories. The final part follows formally from fact that Lf^* and Rf_* are adjoint; compare with Categories, Lemma 4.24.4. \square

Lemma 21.28.3. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Let K be an object of D(\mathcal{O}_\mathcal {C}). Assume

  1. f is flat,

  2. K is bounded below,

  3. f^*Rf_*H^ q(K) \to H^ q(K) is an isomorphism.

Then f^*Rf_*K \to K is an isomorphism.

Proof. Observe that f^*Rf_*K \to K is an isomorphism if and only if it is an isomorphism on cohomology sheaves H^ j. Observe that H^ j(f^*Rf_*K) = f^*H^ j(Rf_*K) = f^*H^ j(Rf_*\tau _{\leq j}K) = H^ j(f^*Rf_*\tau _{\leq j}K). Hence we may assume that K is bounded. Then property (3) tells us the cohomology sheaves are in the triangulated subcategory D' \subset D(\mathcal{O}_\mathcal {C}) of Lemma 21.28.2. Hence K is in it too. \square

Lemma 21.28.4. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Let K be an object of D(\mathcal{O}_\mathcal {D}). Assume

  1. f is flat,

  2. K is bounded below,

  3. H^ q(K) \to Rf_*f^*H^ q(K) is an isomorphism.

Then K \to Rf_*f^*K is an isomorphism.

Proof. Observe that K \to Rf_*f^*K is an isomorphism if and only if it is an isomorphism on cohomology sheaves H^ j. Observe that H^ j(Rf_*f^*K) = H^ j(Rf_*\tau _{\leq j}f^*K) = H^ j(Rf_*f^*\tau _{\leq j}K). Hence we may assume that K is bounded. Then property (3) tells us the cohomology sheaves are in the triangulated subcategory D' \subset D(\mathcal{O}_\mathcal {D}) of Lemma 21.28.1. Hence K is in it too. \square

Lemma 21.28.5. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') be a morphism of ringed topoi. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume

  1. f is flat,

  2. f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},

  3. \mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}').

Then f^* : D_{\mathcal{A}'}^+(\mathcal{O}') \to D_\mathcal {A}^+(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}^+(\mathcal{O}) \to D_{\mathcal{A}'}^+(\mathcal{O}').

Proof. By assumptions (2) and (3) and Lemmas 21.28.4 and 21.28.1 we see that f^* : D_{\mathcal{A}'}^+(\mathcal{O}') \to D_\mathcal {A}^+(\mathcal{O}) is fully faithful. Let \mathcal{F} \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}). Then we can write \mathcal{F} = f^*\mathcal{F}'. Then Rf_*\mathcal{F} = Rf_* f^*\mathcal{F}' = \mathcal{F}'. In particular, we have R^ pf_*\mathcal{F} = 0 for p > 0 and f_*\mathcal{F} \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'). Thus for any K \in D^+_\mathcal {A}(\mathcal{O}) we see, using the spectral sequence E_2^{p, q} = R^ pf_*H^ q(K) converging to R^{p + q}f_*K, that Rf_*K is in D^+_{\mathcal{A}'}(\mathcal{O}'). Of course, it also follows from Lemmas 21.28.3 and 21.28.2 that Rf_* : D_\mathcal {A}^+(\mathcal{O}) \to D_{\mathcal{A}'}^+(\mathcal{O}') is fully faithful. Since f^* and Rf_* are adjoint we then get the result of the lemma, for example by Categories, Lemma 4.24.4. \square

Lemma 21.28.6.reference Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') be a morphism of ringed topoi. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume

  1. f is flat,

  2. f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},

  3. \mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'),

  4. \mathcal{C}, \mathcal{O}, \mathcal{A} satisfy the assumption of Situation 21.25.1,

  5. \mathcal{C}', \mathcal{O}', \mathcal{A}' satisfy the assumption of Situation 21.25.1.

Then f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}').

Proof. Since f^* is exact, it is clear that f^* defines a functor f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) as in the statement of the lemma and that moreover this functor commutes with the truncation functors \tau _{\geq -n}. We already know that f^* and Rf_* are quasi-inverse equivalence on the corresponding bounded below categories, see Lemma 21.28.5. By Lemma 21.25.4 with N = 0 we see that Rf_* indeed defines a functor Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}') and that moreover this functor commutes with the truncation functors \tau _{\geq -n}. Thus for K in D_\mathcal {A}(\mathcal{O}) the map f^*Rf_*K \to K is an isomorphism as this is true on trunctions. Similarly, for K' in D_{\mathcal{A}'}(\mathcal{O}') the map K' \to Rf_*f^*K' is an isomorphism as this is true on trunctions. This finishes the proof. \square

Lemma 21.28.7.reference Let f : (\mathcal{C}, \mathcal{O}) \to (\mathcal{C}', \mathcal{O}') be a morphism of ringed sites. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume

  1. f is flat,

  2. f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},

  3. \mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'),

  4. \mathcal{C}, \mathcal{O}, \mathcal{A} satisfy the assumption of Situation 21.25.1,

  5. f : (\mathcal{C}, \mathcal{O}) \to (\mathcal{C}', \mathcal{O}') and \mathcal{A} satisfy the assumption of Situation 21.25.5.

Then f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}').

Proof. The proof of this lemma is exactly the same as the proof of Lemma 21.28.6 except the reference to Lemma 21.25.4 is replaced by a reference to Lemma 21.25.6. \square


Comments (0)


Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.