In this section we discuss only to what extent a morphism of ringed topoi determines an embedding from the derived category downstairs to the derived category upstairs. Here is a typical result.
Lemma 21.28.1. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Consider the full subcategory D' \subset D(\mathcal{O}_\mathcal {D}) consisting of objects K such that
K \longrightarrow Rf_*Lf^*K
is an isomorphism. Then D' is a saturated triangulated strictly full subcategory of D(\mathcal{O}_\mathcal {D}) and the functor Lf^* : D' \to D(\mathcal{O}_\mathcal {C}) is fully faithful.
Proof.
See Derived Categories, Definition 13.6.1 for the definition of saturated in this setting. See Derived Categories, Lemma 13.4.16 for a discussion of triangulated subcategories. The canonical map of the lemma is the unit of the adjoint pair of functors (Lf^*, Rf_*), see Lemma 21.19.1. Having said this the proof that D' is a saturated triangulated subcategory is omitted; it follows formally from the fact that Lf^* and Rf_* are exact functors of triangulated categories. The final part follows formally from fact that Lf^* and Rf_* are adjoint; compare with Categories, Lemma 4.24.4.
\square
Lemma 21.28.2. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Consider the full subcategory D' \subset D(\mathcal{O}_\mathcal {C}) consisting of objects K such that
Lf^*Rf_*K \longrightarrow K
is an isomorphism. Then D' is a saturated triangulated strictly full subcategory of D(\mathcal{O}_\mathcal {C}) and the functor Rf_* : D' \to D(\mathcal{O}_\mathcal {D}) is fully faithful.
Proof.
See Derived Categories, Definition 13.6.1 for the definition of saturated in this setting. See Derived Categories, Lemma 13.4.16 for a discussion of triangulated subcategories. The canonical map of the lemma is the counit of the adjoint pair of functors (Lf^*, Rf_*), see Lemma 21.19.1. Having said this the proof that D' is a saturated triangulated subcategory is omitted; it follows formally from the fact that Lf^* and Rf_* are exact functors of triangulated categories. The final part follows formally from fact that Lf^* and Rf_* are adjoint; compare with Categories, Lemma 4.24.4.
\square
Lemma 21.28.3. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Let K be an object of D(\mathcal{O}_\mathcal {C}). Assume
f is flat,
K is bounded below,
f^*Rf_*H^ q(K) \to H^ q(K) is an isomorphism.
Then f^*Rf_*K \to K is an isomorphism.
Proof.
Observe that f^*Rf_*K \to K is an isomorphism if and only if it is an isomorphism on cohomology sheaves H^ j. Observe that H^ j(f^*Rf_*K) = f^*H^ j(Rf_*K) = f^*H^ j(Rf_*\tau _{\leq j}K) = H^ j(f^*Rf_*\tau _{\leq j}K). Hence we may assume that K is bounded. Then property (3) tells us the cohomology sheaves are in the triangulated subcategory D' \subset D(\mathcal{O}_\mathcal {C}) of Lemma 21.28.2. Hence K is in it too.
\square
Lemma 21.28.4. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}_\mathcal {C}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{D}), \mathcal{O}_\mathcal {D}) be a morphism of ringed topoi. Let K be an object of D(\mathcal{O}_\mathcal {D}). Assume
f is flat,
K is bounded below,
H^ q(K) \to Rf_*f^*H^ q(K) is an isomorphism.
Then K \to Rf_*f^*K is an isomorphism.
Proof.
Observe that K \to Rf_*f^*K is an isomorphism if and only if it is an isomorphism on cohomology sheaves H^ j. Observe that H^ j(Rf_*f^*K) = H^ j(Rf_*\tau _{\leq j}f^*K) = H^ j(Rf_*f^*\tau _{\leq j}K). Hence we may assume that K is bounded. Then property (3) tells us the cohomology sheaves are in the triangulated subcategory D' \subset D(\mathcal{O}_\mathcal {D}) of Lemma 21.28.1. Hence K is in it too.
\square
Lemma 21.28.5. Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') be a morphism of ringed topoi. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume
f is flat,
f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},
\mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}').
Then f^* : D_{\mathcal{A}'}^+(\mathcal{O}') \to D_\mathcal {A}^+(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}^+(\mathcal{O}) \to D_{\mathcal{A}'}^+(\mathcal{O}').
Proof.
By assumptions (2) and (3) and Lemmas 21.28.4 and 21.28.1 we see that f^* : D_{\mathcal{A}'}^+(\mathcal{O}') \to D_\mathcal {A}^+(\mathcal{O}) is fully faithful. Let \mathcal{F} \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}). Then we can write \mathcal{F} = f^*\mathcal{F}'. Then Rf_*\mathcal{F} = Rf_* f^*\mathcal{F}' = \mathcal{F}'. In particular, we have R^ pf_*\mathcal{F} = 0 for p > 0 and f_*\mathcal{F} \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'). Thus for any K \in D^+_\mathcal {A}(\mathcal{O}) we see, using the spectral sequence E_2^{p, q} = R^ pf_*H^ q(K) converging to R^{p + q}f_*K, that Rf_*K is in D^+_{\mathcal{A}'}(\mathcal{O}'). Of course, it also follows from Lemmas 21.28.3 and 21.28.2 that Rf_* : D_\mathcal {A}^+(\mathcal{O}) \to D_{\mathcal{A}'}^+(\mathcal{O}') is fully faithful. Since f^* and Rf_* are adjoint we then get the result of the lemma, for example by Categories, Lemma 4.24.4.
\square
Lemma 21.28.6.reference Let f : (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}), \mathcal{O}) \to (\mathop{\mathit{Sh}}\nolimits (\mathcal{C}'), \mathcal{O}') be a morphism of ringed topoi. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume
f is flat,
f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},
\mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'),
\mathcal{C}, \mathcal{O}, \mathcal{A} satisfy the assumption of Situation 21.25.1,
\mathcal{C}', \mathcal{O}', \mathcal{A}' satisfy the assumption of Situation 21.25.1.
Then f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}').
Proof.
Since f^* is exact, it is clear that f^* defines a functor f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) as in the statement of the lemma and that moreover this functor commutes with the truncation functors \tau _{\geq -n}. We already know that f^* and Rf_* are quasi-inverse equivalence on the corresponding bounded below categories, see Lemma 21.28.5. By Lemma 21.25.4 with N = 0 we see that Rf_* indeed defines a functor Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}') and that moreover this functor commutes with the truncation functors \tau _{\geq -n}. Thus for K in D_\mathcal {A}(\mathcal{O}) the map f^*Rf_*K \to K is an isomorphism as this is true on trunctions. Similarly, for K' in D_{\mathcal{A}'}(\mathcal{O}') the map K' \to Rf_*f^*K' is an isomorphism as this is true on trunctions. This finishes the proof.
\square
Lemma 21.28.7.reference Let f : (\mathcal{C}, \mathcal{O}) \to (\mathcal{C}', \mathcal{O}') be a morphism of ringed sites. Let \mathcal{A} \subset \textit{Mod}(\mathcal{O}) and \mathcal{A}' \subset \textit{Mod}(\mathcal{O}') be weak Serre subcategories. Assume
f is flat,
f^* induces an equivalence of categories \mathcal{A}' \to \mathcal{A},
\mathcal{F}' \to Rf_*f^*\mathcal{F}' is an isomorphism for \mathcal{F}' \in \mathop{\mathrm{Ob}}\nolimits (\mathcal{A}'),
\mathcal{C}, \mathcal{O}, \mathcal{A} satisfy the assumption of Situation 21.25.1,
f : (\mathcal{C}, \mathcal{O}) \to (\mathcal{C}', \mathcal{O}') and \mathcal{A} satisfy the assumption of Situation 21.25.5.
Then f^* : D_{\mathcal{A}'}(\mathcal{O}') \to D_\mathcal {A}(\mathcal{O}) is an equivalence of categories with quasi-inverse given by Rf_* : D_\mathcal {A}(\mathcal{O}) \to D_{\mathcal{A}'}(\mathcal{O}').
Proof.
The proof of this lemma is exactly the same as the proof of Lemma 21.28.6 except the reference to Lemma 21.25.4 is replaced by a reference to Lemma 21.25.6.
\square
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