The Stacks project

75.4 Derived category of quasi-coherent modules on the small étale site

Let $X$ be a scheme. In this section we show that $D_\mathit{QCoh}(\mathcal{O}_ X)$ can be defined in terms of the small étale site $X_{\acute{e}tale}$ of $X$. Denote $\mathcal{O}_{\acute{e}tale}$ the structure sheaf on $X_{\acute{e}tale}$. Consider the morphism of ringed sites

75.4.0.1
\begin{equation} \label{spaces-perfect-equation-epsilon} \epsilon : (X_{\acute{e}tale}, \mathcal{O}_{\acute{e}tale}) \longrightarrow (X_{Zar}, \mathcal{O}_ X). \end{equation}

denoted $\text{id}_{small, {\acute{e}tale}, Zar}$ in Descent, Lemma 35.8.5.

Lemma 75.4.1. The morphism $\epsilon $ of (75.4.0.1) is a flat morphism of ringed sites. In particular the functor $\epsilon ^* : \textit{Mod}(\mathcal{O}_ X) \to \textit{Mod}(\mathcal{O}_{\acute{e}tale})$ is exact. Moreover, if $\epsilon ^*\mathcal{F} = 0$, then $\mathcal{F} = 0$.

Proof. The flatness of the morphism $\epsilon $ is Descent, Lemma 35.10.1. Here is another proof. We have to show that $\mathcal{O}_{\acute{e}tale}$ is a flat $\epsilon ^{-1}\mathcal{O}_ X$-module. To do this it suffices to check $\mathcal{O}_{X, x} \to \mathcal{O}_{{\acute{e}tale}, \overline{x}}$ is flat for any geometric point $\overline{x}$ of $X$, see Modules on Sites, Lemma 18.39.3, Sites, Lemma 7.34.2, and Étale Cohomology, Remarks 59.29.11. By Étale Cohomology, Lemma 59.33.1 we see that $\mathcal{O}_{{\acute{e}tale}, \overline{x}}$ is the strict henselization of $\mathcal{O}_{X, x}$. Thus $\mathcal{O}_{X, x} \to \mathcal{O}_{{\acute{e}tale}, \overline{x}}$ is faithfully flat by More on Algebra, Lemma 15.45.1.

The exactness of $\epsilon ^*$ follows from the flatness of $\epsilon $ by Modules on Sites, Lemma 18.31.2.

Let $\mathcal{F}$ be an $\mathcal{O}_ X$-module. If $\epsilon ^*\mathcal{F} = 0$, then with notation as above

\[ 0 = \epsilon ^*\mathcal{F}_{\overline{x}} = \mathcal{F}_ x \otimes _{\mathcal{O}_{X, x}} \mathcal{O}_{{\acute{e}tale}, \overline{x}} \]

(Modules on Sites, Lemma 18.36.4) for all geometric points $\overline{x}$. By faithful flatness of $\mathcal{O}_{X, x} \to \mathcal{O}_{{\acute{e}tale}, \overline{x}}$ we conclude $\mathcal{F}_ x = 0$ for all $x \in X$. $\square$

Let $X$ be a scheme. Notation as in (75.4.0.1). Recall that $\epsilon ^* : \mathit{QCoh}(\mathcal{O}_ X) \to \mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ is an equivalence by Descent, Proposition 35.8.9 and Remark 35.8.6. Moreover, $\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ forms a Serre subcategory of $\textit{Mod}(\mathcal{O}_{\acute{e}tale})$ by Descent, Lemma 35.10.2. Hence we can let $D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ be the triangulated subcategory of $D(\mathcal{O}_{\acute{e}tale})$ whose objects are the complexes with quasi-coherent cohomology sheaves, see Derived Categories, Section 13.17. The functor $\epsilon ^*$ is exact (Lemma 75.4.1) hence induces $\epsilon ^* : D(\mathcal{O}_ X) \to D(\mathcal{O}_{\acute{e}tale})$ and since pullbacks of quasi-coherent modules are quasi-coherent also $\epsilon ^* : D_\mathit{QCoh}(\mathcal{O}_ X) \to D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$.

Lemma 75.4.2. Let $X$ be a scheme. The functor $\epsilon ^* : D_\mathit{QCoh}(\mathcal{O}_ X) \to D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ defined above is an equivalence.

Proof. We will prove this by showing the functor $R\epsilon _* : D(\mathcal{O}_{\acute{e}tale}) \to D(\mathcal{O}_ X)$ induces a quasi-inverse. We will use freely that $\epsilon _*$ is given by restriction to $X_{Zar} \subset X_{\acute{e}tale}$ and the description of $\epsilon ^* = \text{id}_{small, {\acute{e}tale}, Zar}^*$ in Descent, Lemma 35.8.5.

For a quasi-coherent $\mathcal{O}_ X$-module $\mathcal{F}$ the adjunction map $\mathcal{F} \to \epsilon _*\epsilon ^*\mathcal{F}$ is an isomorphism by the fact that $\mathcal{F}^ a$ (Descent, Definition 35.8.2) is a sheaf as proved in Descent, Lemma 35.8.1. Conversely, every quasi-coherent $\mathcal{O}_{\acute{e}tale}$-module $\mathcal{H}$ is of the form $\epsilon ^*\mathcal{F}$ for some quasi-coherent $\mathcal{O}_ X$-module $\mathcal{F}$, see Descent, Proposition 35.8.9. Then $\mathcal{F} = \epsilon _*\mathcal{H}$ by what we just said and we conclude that the adjunction map $\epsilon ^*\epsilon _*\mathcal{H} \to \mathcal{H}$ is an isomorphism for all quasi-coherent $\mathcal{O}_{\acute{e}tale}$-modules $\mathcal{H}$.

Let $E$ be an object of $D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale})$ and denote $\mathcal{H}^ q = H^ q(E)$ its $q$th cohomology sheaf. Let $\mathcal{B}$ be the set of affine objects of $X_{\acute{e}tale}$. Then $H^ p(U, \mathcal{H}^ q) = 0$ for all $p > 0$, all $q \in \mathbf{Z}$, and all $U \in \mathcal{B}$, see Descent, Proposition 35.9.3 and Cohomology of Schemes, Lemma 30.2.2. By Cohomology on Sites, Lemma 21.23.11 this means that

\[ H^ q(U, E) = H^0(U, \mathcal{H}^ q) \]

for all $U \in \mathcal{B}$. In particular, we find that this holds for affine opens $U \subset X$. It follows that the $q$th cohomology of $R\epsilon _*E$ over $U$ is the value of the sheaf $\epsilon _*\mathcal{H}^ q$ over $U$. Applying sheafification we obtain

\[ H^ q(R\epsilon _*E) = \epsilon _*\mathcal{H}^ q \]

which in particular shows that $R\epsilon _*$ induces a functor $D_\mathit{QCoh}(\mathcal{O}_{\acute{e}tale}) \to D_\mathit{QCoh}(\mathcal{O}_ X)$. Since $\epsilon ^*$ is exact we then obtain $H^ q(\epsilon ^*R\epsilon _*E) = \epsilon ^*\epsilon _*\mathcal{H}^ q = \mathcal{H}^ q$ (by discussion above). Thus the adjunction map $\epsilon ^*R\epsilon _*E \to E$ is an isomorphism.

Conversely, for $F \in D_\mathit{QCoh}(\mathcal{O}_ X)$ the adjunction map $F \to R\epsilon _*\epsilon ^*F$ is an isomorphism for the same reason, i.e., because the cohomology sheaves of $R\epsilon _*\epsilon ^*F$ are isomorphic to $\epsilon _*H^ m(\epsilon ^*F) = \epsilon _*\epsilon ^*H^ m(F) = H^ m(F)$. $\square$


Comments (0)


Post a comment

Your email address will not be published. Required fields are marked.

In your comment you can use Markdown and LaTeX style mathematics (enclose it like $\pi$). A preview option is available if you wish to see how it works out (just click on the eye in the toolbar).

Unfortunately JavaScript is disabled in your browser, so the comment preview function will not work.

All contributions are licensed under the GNU Free Documentation License.




In order to prevent bots from posting comments, we would like you to prove that you are human. You can do this by filling in the name of the current tag in the following input field. As a reminder, this is tag 071P. Beware of the difference between the letter 'O' and the digit '0'.