Lemma 30.3.4. Let f : X \to Y be a quasi-compact morphism with X and Y quasi-separated. If R^1f_*\mathcal{I} = 0 for every quasi-coherent sheaf of ideals \mathcal{I} on X, then f is affine.
Proof. Let V \subset Y be an affine open subscheme. We have to show that U = f^{-1}(V) is affine. The inclusion morphism V \to Y is quasi-compact by Schemes, Lemma 26.21.14. Hence the base change U \to X is quasi-compact, see Schemes, Lemma 26.19.3. Thus any quasi-coherent sheaf of ideals \mathcal{I} on U extends to a quasi-coherent sheaf of ideals on X, see Properties, Lemma 28.22.1. Since the formation of R^1f_* is local on Y (Cohomology, Section 20.7) we conclude that R^1(U \to V)_*\mathcal{I} = 0 by the assumption in the lemma. Hence by the Leray Spectral sequence (Cohomology, Lemma 20.13.4) we conclude that H^1(U, \mathcal{I}) = H^1(V, (U \to V)_*\mathcal{I}). Since (U \to V)_*\mathcal{I} is quasi-coherent by Schemes, Lemma 26.24.1, we have H^1(V, (U \to V)_*\mathcal{I}) = 0 by Lemma 30.2.2. Thus we find that U is affine by Lemma 30.3.1. \square
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